Answer:
i wanna say 11 forgive me if wrong.
Explanation:
Answer:
d = 69 .57 meter
Explanation:
First case
Speed of car ( v ) = 20.5 mi/h = 9.164 M/S
distance ( d ) = 11.6 meter ( m = mass of the car )
Work done = 0.5 m v² = 0.5 * 9.164² * m J = 41.99 m J
Force = ( workdone /distance ) = ( 41.99 m / 11.6 ) = 3.619 m N
Second case
v = 50.2 mi/h = 22.44135 m/s
d = ?
Work done = 0.5 * 22.44² * m J = 251.7768 * m J
Since the braking force remains the same .
3.619 m = ( 251.7768 m / d )
d = 69 .57 meter
We know, Momentum is the product of mass and velocity. As velocity is equal, momentum of Truck will be greater as mass of Truck is greater than the scooter. As momentum is greater from truck side, it will transfer the same amount to the scooter, so it flies away
Hope this helps!
Answer:
Period of oscillation = 1.33 seconds
Explanation:
The period of oscillation is given by:
T = 2π√[I/(MgL)]
for I = 2MR² and L = R,
Given: L = 0.22m = R
T = 2π√[2R/g]
T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]
T = 6.284 Sqrt(0.44/9.8)
T = 6.284 Sqrt(0.0449)
T = 6.284 × 0.2119
T = 1.33 sec
Acceleration is defined as the rate of change of velocity, which, simply put, is a mouthful to describe how fast something speeds up, slows down, or turns. The equation for acceleration is
a = Δv / Δt,
or your final velocity - your starting velocity, then divided by the amount of time. It can also be expressed as
a = (Vf - Vi) / t,
Where Vf is your final velocity, Vi is your initial velocity, and t is the time traveled.
The question gives us that the helicopter moves from a starting velocity of 30 m/s to a final velocity of 40 m/s in the span of 5 seconds. This means we can fill in the variables to the equation, where
Vf = 40,
Vi = 30, and
t = 5.
Plug these known variables into the original equation, and we get
a = (Vf - Vi) / t = (40 - 30) / 5.
From here, the answer comes down to 10 / 5, or 2 m/s^2.
Hope this helps! If you have any questions, don't hesitate to ask :D
