Answer:
This is required answer.
Explanation:
Given that:
1. by addition the ammonia to acetic acid
using balanced chemical equation:
ammonium acetate:
The balanced equation is:
NH₃ + H₂O ===> NH₄OH
when ammonia gas dissolves in water then we get the base in form of ammonium hydroxide.
When NH₄OH reacts with CH₃COOH then we get ammonium acetate and water
NH₄OH + CH₃COOH ===> [CH₃COO]- & NH₄+ & H₂O
So, we can say that,
when we are adding an acid and a base together then we get the product of H₂O and given elements.
2. addition of barium hydroxide to sulfuric acid:
The balanced equation is :
H₂SO4+ Ba(OH)₂--> BaSO₄+ 2H₂O
when acid and base reacts together than we get barium sulphate and water
when sulfuric acid and barium hydroxide.
Hence, this is required answer.
Melting phase, the ice is melting into water.
1.3 atmosphere is 131.722 Kilopascal
We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>
Answer:
1 mol SO2 contains 6.0213*10^23 molecules
6.023*10^24 molecules = 10 mol SO2
Equation
S(s) + O2(g) → SO2(g)
1 mol S reacts with 1 mol O2 to prepare 1 mol SO2
To prepare 10 mol SO2 you require : 10 mol S plus 10 mol O2
And that is the answer to the question
If you want a mass :
Molar mass S = 32 g/mol You require 10 mol = 320 g
Molar mass O2 = 32 g/mol :You require 10 mol = 320 g
