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Tems11 [23]
3 years ago
6

Plz help Which is an example of an abiotic factor interacting with a biotic factor in an ecosystem?

Chemistry
1 answer:
Svetlanka [38]3 years ago
6 0
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How many grams of water can be produced from 4.6 grams of Hydrogen and 7.3 grams of Oxygen?
12345 [234]

Answer:

The answer to your question is 8.21 g of H₂O

Explanation:

Data

mas of water = ?

mass of hydrogen = 4.6 g

mass of oxygen = 7.3 g

Balanced chemical reaction

                   2H₂  +  O₂  ⇒   2H₂O

Process

1.- Calculate the atomic mass of the reactants

Hydrogen = 4 x 1 = 4 g

Oxygen = 16 x 2 = 32 g

2.- Calculate the limiting reactant

Theoretical yield = H₂/O₂ = 4 / 32 = 0.125

Experimental yield = H₂/ O₂ = 4.6/7.3 = 0.630

From the results, we conclude that the limiting reactant is Oxygen because the experimental yield was higher than the theoretical yield.

3.- Calculate the mass of water

                   32 g of O₂ ---------------- 36 g of water

                   7.3 g of O₂ ---------------   x

                          x = (7.3 x 36) / 32

                          x = 262.8 / 32

                          x = 8.21 g of H₂O

4 0
3 years ago
What is the sequence in the formation of the Earth and the Universe?
Bezzdna [24]

Answer:

The Earth formed billions of years after the Universe formed

Explanation:

The "universe" is said to have been formed <em>billions of year ago</em> through an explosion. This was called the <em>"Big Bang Theory." </em>This lead to the<u> expansion of the universe</u> owing to its high temperature and density. After which, the universe cooled down. Galaxies and stars were then formed. Some of the stars died due to explosion, which then led to the <u>creation of planets</u>. Such formation of the planets happened around <u>4.5 billion years ago.</u> This is <em>9.3 billions of years later</em> than the universe was formed<em> (13.8 billions of years ago)</em>. So, this explains the answer.

3 0
2 years ago
c. The reaction Br2 (l) --&gt; Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a
egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0
3 years ago
Be sure to answer all parts. Rubidium and bromine atoms are depicted at right. Answer the following questions. (a) What is the c
finlep [7]

The complete question is found on the image attached.

Answer:

a) Rb= +1, Br= -1

b)Bromide and rubidium ions are related to krypton

c) C

Explanation:

Rubidium is found in group 1 with a charge of +1. Bromine is found in group 17 with a charge of -1. Both species have the same configuration as krypton. The ionic sizes of the ions are a very similar to each other Rb+ is 166 while Be is 167.

This RbBr is an ionic compound.

6 0
3 years ago
Pretend you are the size of an atom and you are observing a reaction between a potassium ion and a fluorine atom. Describe how a
Elena L [17]
Due to periodic trends potassium would lose its one valence electron to have a more stable electron configuration equivalent to that of argon, which is a noble gas with a full octet. Fluorine would gain one valence electron to get a full octet equivalent to that of neon. Since potassium lost an electron it now has a positive charge and since fluorine gained an electron it is now negative. Since both are more stable this way as a full octet they will no longer exchange electrons but the positive potassium and negative fluorine will pull towards each other strongly forming an ionic bond.
6 0
2 years ago
Read 2 more answers
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