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2 years ago

567898765456787654567876567876+9999999999999999999999999999999

Mathematics

2 answers:

Anna007 [38]2 years ago

7 0

Answer:

I'm just gonna take your points

Step-by-step explanation:

sorry

KonstantinChe [14]2 years ago

5 0

Answer:

1.05678988E31

Step-by-step explanation:

You might be interested in

Will give 50 points

mafiozo [28]

Answer:

120.96$

Step-by-step explanation:

150$ - 25% = 112$

112$ + 8% = 120.96$

Hope this helps!!

7 0

3 years ago

A small publishing company is planning to publish a new book. The production costs will include one-time fixed costs (such as ed

zhuklara [117]

Answer:

For the cost from the two methods to be equal, 3,200 books have to be produced

Step-by-step explanation:

In this question, we are asked to calculate the number of books that will be produced for two methods of production having different fixed and variable costs to have the same production cost.

Since the number of books is something we do not know, let’s represent it with a variable called c.

For the first production method, the cost of production will be ; 58,881 + 8.50c

For the second production method, the cost of production will be; 18,081 + 21.25c

Now since they are said to be equal, we proceed to equate both;

58,881 + 8.5c = 18,081 + 21.25c

58,881-18,081 = 21.25c - 8.5c

40,800 = 12.75c

c = 40,800/12.75

c = 3,200 books

4 0

3 years ago

Solve for x and y:<br> 3/x -1/y =13/10<br> 1/x + 2/y =9/10

harkovskaia [24]

Answer:

(x, y) = (2, 5)

Step-by-step explanation:

I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...

3x' -y' = 13/10

x' +2y' = 9/10

Adding twice the first equation to the second, we get ...

2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)

7x' = 35/10 . . . . . . simplify

x' = 5/10 = 1/2 . . . . divide by 7

Using the first equation to find y', we have ...

y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5

So, the solution is ...

x = 1/x' = 1/(1/2) = 2

y = 1/y' = 1/(1/5) = 5

(x, y) = (2, 5)

_____

The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.