All categories

3 years ago

Find the circumference of a circle with diameter,

Mathematics

1 answer:

Elena L [17]3 years ago

3 0

Answer:

Step-by-step explanation:

The circumference of the circle is $2\pi r$ or $\pi d$

Where r is the radius and d is the diameter. The diameter is 24cm and the radius being half the length of the diameter is 12cm.

So the circumference = 2* $\pi$ *r = $\pi$ *24 = 24 $\pi$

You might be interested in

Which best describes the relationship between the successive terms in the sequence shown?

Alex Ar [27]

Given series is 2.4,-4.8,9.6,-19.2

To find whether it has common difference or common ratio let us find few differences and few ratios of consecutive terms.

Common difference of first 2 terms = 2nd term - first term = -4.8-2.4 = -7.2

Common difference of 2nd and 3rd terms = 3rd term - 2nd term = 9.6-(-4.8) = 14.4

Since those common differences are not equal the given series does not have common difference at all.

To check if it has common ratio or not let us find few ratios of consecutive terms.

Common ratio of first 2 terms = $\frac{2nd term}{first term}$ = $\frac{-4.8}{2.4} = -2$

Common ratio of 2nd and 3rd terms = $\frac{3rd term}{2nd term} = \frac{9.6}{-4.8} = -2.0$

So, the given series has common ratio as -2.0

7 0

3 years ago

Read 2 more answers

Witch is greater 1/5 or 500 pounds

Travka [436]

I believe it is 500 pounds b cause one out of 5 is less than 500 out of 1000 or 500 pounds

3 0

3 years ago

Denise is a professional swimmer who trains, in part, by running. she would like to estimate the average number of miles she run

SSSSS [86.1K]

Given:
n = 20, sample size
xbar = 17.5, sample mean
s = 3.8, sample standard deiation
99% confidence interval

The degrees of freedom is
df = n-1 = 19

We do not know the population standard deviation, so we should determine t* that corresponds to df = 19.
From a one-tailed distribution, 99% CI means using a p-value of 0.005.
Obtain
t* = 2.8609.

The 99% confidence interval is
xbar +/- t*(s/√n)

t*(s/√n) = 2.8609*(3.8/√20) = 2.4309
The 99% confidence interval is
(17.5 - 2.4309, 17.5 + 2.4309) = (15.069, 19.931)

Answer: The 99% confidence interval is (15.07, 19.93)

4 0

4 years ago

Can someone help me please thank you

serious [3.7K]

Answer:

15 <u><</u> x <u><</u> 18? I don't know. Is that what you're looking for?

Step-by-step explanation:

3 0

3 years ago

WILL MARK AS BRAINLIEST IF YOU ANSWER THESE CORRECTLY*** Can someone please help me with these math questions? I would really ap

igor_vitrenko [27]

ANSWER:

Question a):

$\dfrac{5}{3}*x= \dfrac{5}{6}\\ \\ \\ \dfrac{5}{3}x= \dfrac{5}{6}\\ \\6(5x)=3(5)\\ \\30x=15\\ \\x= \dfrac{15}{30}\\ \\ \\x= \dfrac{\not{15}}{\not{30}}\\ \\ \\x= \dfrac{1}{2}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question b):

$\dfrac{5}{3}\div{x}= \dfrac{10}{9}\\ \\ \\ \dfrac{5}{3}\div{ \dfrac{x}{1} }= \dfrac{10}{9}\\ \\ \\ \dfrac{5*1}{3*x}= \dfrac{10}{9}\\ \\ \\ \dfrac{5}{3x}= \dfrac{10}{9}\\ \\9(5)=10(3x)\\ \\45=30x\\ \\ \dfrac{45}{30}=x\\ \\ \\ \dfrac{\not{45}}{\not{30}}=x\\ \\ \\ \dfrac{3}{2}=x\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question c):

$12\%*x= \dfrac{3}{4}\\ \\ \\ \dfrac{12}{100}*x= \dfrac{3}{4}\\ \\ \\ \dfrac{\not{12}}{\not{100}}x= \dfrac{3}{4}\\ \\ \\ \dfrac{3}{25}x= \dfrac{3}{4}\\ \\4(3x)=3(25)\\ \\12x=75\\ \\x= \dfrac{75}{12}\\ \\ \\x= \dfrac{\not{75}}{\not{12}}\\ \\ \\x= \dfrac{25}{4}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question d):

$\dfrac{12}{7}*x= \dfrac{18}{35}\\ \\ \\ \dfrac{12}{7}x= \dfrac{18}{35}\\ \\35(12x)=7(18)\\ \\420x=126\\ \\x= \dfrac{126}{420}\\ \\ \\x= \dfrac{\not{126}}{\not{420}}\\ \\ \\x= \dfrac{3}{10}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question e):

$x\div{ \dfrac{8}{11} }= \dfrac{22}{7}\\ \\ \\ \dfrac{x}{1}\div{ \dfrac{8}{11} }= \dfrac{22}{7}\\ \\ \\ \dfrac{11*x}{8*1}= \dfrac{22}{7}\\ \\ \\ \dfrac{11x}{8}= \dfrac{22}{7}\\ \\7(11x)=8(22)\\ \\77x=176\\ \\x= \dfrac{176}{77}\\ \\ \\x= \dfrac{\not{176}}{\not{77}}\\ \\ \\x= \dfrac{16}{7}\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

Question f):

$120\%\div{x}= \dfrac{14}{15}\\ \\ \\ \dfrac{120}{100}\div{x}= \dfrac{14}{15}\\ \\ \\ \dfrac{\not{120}}{\not{100}}\div{}x= \dfrac{14}{15}\\ \\ \\ \dfrac{6}{5}\div{x}= \dfrac{14}{15}\\ \\ \\ \dfrac{6}{5}\div{ \dfrac{x}{1} }= \dfrac{14}{15}\\ \\ \\ \dfrac{1*6}{5*x}= \dfrac{14}{15}\\ \\ \\ \dfrac{6}{5x}= \dfrac{14}{15}\\ \\6(15)=14(5x)\\ \\90=70x\\ \\ \dfrac{90}{70}=x\\ \\ \\ \dfrac{\not{90}}{\not{70}}=x\\ \\ \\ \dfrac{9}{7}=x\quad\Longrightarrow\boxed{\mathbb{ANSWER\ \checkmark}}$

$\textbf{HOPE\ THIS\ HELPS...!!}$

3 0

3 years ago