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lana66690 [7]
3 years ago
7

A-y= b+y/a make y subject

Mathematics
1 answer:
Sav [38]3 years ago
8 0

Answer:

y = \frac{a^2-ab}{a+1}

Step-by-step explanation:

a - y = b + \frac{y}{a} ( multiply through by a to clear the fraction )

a² - ay = ab + y ( subtract y from both sides )

a² - ay - y = ab ( subtract a² from both sides )

- ay - y = ab - a² ← factor out y from each term on the left side

y(- a - 1) = ab - a² ( divide both sides by - a - 1 )

y = \frac{ab-a^2}{-a-1} ( multiply numerator/ denominator by - 1 )

y = \frac{a^2-ab}{a+1}

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The coordinate points of triangle ABC are A(5,0), B(2,1), and C(-4,-4). If the triangle is translated 8 units right and 5 units
Studentka2010 [4]

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A(13,-5)

B(10,-4)

C(4,-9)

Step-by-step explanation:

Translation of 8 units right >>> affects the "x" coordinate. Add 8 to each x coordinate.

Translation of 5 units down >>> affects the "y" coordinate. Subtract 5 from each y coordinate.

The coordinates are:

A (5,0)

B (2,1)

C (-4,-4)

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B(2+8,1-5)

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6 0
3 years ago
Compute the sums below. (Assume that the terms in the first sum are consecutive terms of an arithmetic sequence.)
riadik2000 [5.3K]

Answer:

=18975

Step-by-step explanation:

This is an arithmetic sequence

an = a1 +d(n-1)

a1 =9

d = 12-9 = 3

an = 9 +3 (n-1)

The sum of an arithmetic sequence is given by

Sn = n/2 (a1+an)

So we need to determine what number in the sequence 336 is

an = 9 +3 (n-1)

336 = 9 +3(n-1)

Subtract 9 from each side

336-9 =9+-9 + 3(n-1)

327 = 3(n-1)

Divide each side by 3

327/3 =3/3(n-1)

109 = n-1

Add 1 to each side

109+1= n-1+1

110 = n

336 is the 110  term

The sum from 9 to 336

Sn = n/2 (a1+an)

S 110 = 110/2 (9+336)

          = 55 (345)

          =18975

5 0
3 years ago
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