Answer:
B. 112°
Step-by-step explanation:
4x -4 = (3x+4) + (2x-44)
4x -4 = 5x - 40
5x - 4x = -4 + 40
x = 36
∠BCA = 3 * 36 + 4 = 112
The answer is A, 75 degrees
add all like terms
2x+196
all triangles equal 180 degrees
2x+196=180
subtract the 196 from 180
2x= -16
divide
x= -8
plug into angle A
-8+83
A=75
Answer:
well the ratio is 1 : 4 so x is 16
Step-by-step explanation:
After throughfall calculating the multiplication 4505 x 219 in standard algorithm, we have come to find that product is 986595
<h3>What is standard algorithm?</h3>
In elementary math, a standard algorithm or method is a particular computation technique that is typically taught for resolving particular mathematical issues. In general, these techniques include exchanging, regrouping, long division, long multiplication using a standard notation, and standard formulas for average, area, and volume.
These techniques can vary somewhat by country and time, but they typically include these techniques. Similar techniques are also available for more complex functions like square roots, but they are no longer taught in general mathematics classes because calculators are more convenient.
4505 x 219 in standard algorithm is as follows:
⇒ 4 5 0 5
<u>× 2 1 9 </u>
4 0 5 4 5
+ 4 5 0 5
+<u> 9 0 1 0 </u>
9 8 6 5 9 5
Learn more about standard algorithm
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Step-by-step explanation:
Consider the provided information.
The total number of students are: 24+26+21=71
He wants each team will have the same number of students between 5 and 9.
The number between 5 to 9 are 6, 7 and 8.
The number 71 is a prime number so we need to divide the 71 students in group so that minimum students left without team.
Dividing 6 students in each group.
Number of teams: 
= 11 teams and 5 students.
Dividing 7 students in each group.
Number of teams: 
= 10 teams and 1 students.
Dividing 8 students in each group.
Number of teams: 
= 8 teams and 7 students.
Thus, we can not divide 71 students into equal teams, but 70 divided by 7 gives the least students left out i.e 10 teams each with 7 students and only 1 student will remain at last.
