Molar Mass of KCLO3
= 39 + 35.5 + 48 g
= 122.5 g .
So , percentage of Potassium ( K )
= 39 / 122.5 * 100 %
= 31.83 %
Now , percentage of Chlorine ( Cl )
= 35.5 / 122.5 * 100 %
= 28.97 %
So, finally, percentage of Oxygen ( O )
= 48 / 122.5 * 100 %
= 39.18 %
Answer:
You can dissolve about 1g of chloroform in a 100g of water; slightly less if the water is hot. This would not generally be considered 'soluble', but it's not entirely negligible either, depending on your purposes. chloroform is insoluble in water since it does not have any hydrophillic groups.
hope this helps you uwu
Answer:
14 mol O₂
Explanation:
The reaction between CO and O₂ is the following:
CO + O₂ → CO₂
We balance the equation with a coefficient 2 in CO and CO₂ to obtain the same number of O atoms:
2CO + O₂ → 2CO₂
As we can see from the balanced equation, 1 mol of O₂ is required to react with 2 moles of CO. Thus, the conversion factor is 1 mol of O₂/2 mol CO. We multiply the moles of CO by the conversion factor to calculate the moles of O₂ that are required:
28 mol CO x 1 mol of O₂/2 mol CO = 14 mol O₂
You have many different ways possible. If you have a freezer in the classroom you could do that. If you made it really cold in the room and stopped all air flow in the room so it stayed cold you would be able to freeze it.
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