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frutty [35]
3 years ago
9

If the mass of a ball is 20 kg and it accelerates 5 m/s2, find the Force applied to it. F=ma

Chemistry
1 answer:
Annette [7]3 years ago
4 0
F=ma
F=20kg*5m/s2
F=100kg m/s2
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Which of the following gas samples would contain the same amount of gas as 200 mL of helium, He(g), at 25° C and 1 atm?
monitta

Answer:

200\; \rm mL of neon \rm Ne\, (g) at 25^{\circ} \rm C and 1\; \rm atm (the second choice) would contain an equal number of gas particles as 200\; \rm mL\! of \rm He \, (g) at 25^{\circ} \rm C\! and 1\; \rm atm\! (assuming that all four gas samples behave like ideal gases.)

Explanation:

By Avogadro's Law, if the temperature and pressure of two ideal gases is the same, the number of gas particles in each gas would be proportional to the volume of that gas.

All four gas samples in this question share the same temperature and pressure. Hence, if all these gases are ideal gases, the number of gas particles in each sample would be proportional to the volume of that sample. Two of these samples would contain the same number of gas particles if and only if the volume of the two samples is equal to one another.

The second choice, 200\; \rm mL of neon \rm Ne\, (g) at 25^{\circ} \rm C and 1\; \rm atm, is the only choice where the volume of the sample is also 200\; \rm mL \!. Hence, that choice would be the only one with as many gas particles as 200\; \rm mL\! of \rm He \, (g) at 25^{\circ} \rm C\! and 1\; \rm atm\!.

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3 years ago
Can anybody help please
romanna [79]

Answer:

Three hydrogen atoms

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2 years ago
Calculate the number of moles in a 14.5 gram sample of C4H10.
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Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
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Moles=14.5g / 58.14g/mol
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Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
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