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3 years ago

9

If the mass of a ball is 20 kg and it accelerates 5 m/s2, find the Force applied to it. F=ma

1 answer:

Annette [7]3 years ago

4 0

F=ma
F=20kg*5m/s2
F=100kg m/s2

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Which of the following tool components is unlikely to present a hazard

nydimaria [60]

Gloves is the tool component which will unlikely present a hazard in this scenario.

<h3>What is Hazard?</h3>

This is referred to as potential source of harm when performing various types of activities.

Gloves will unlikely cause harm as it is used to prevent the risk of electric shock when handling electrical devices which is why it is the most appropriate choice.

Read more about Hazard here brainly.com/question/7310653

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2 years ago

crash course video about periodic table - The Periodic Table: Crash Course Chemistry #4 - write a reflection about this video

Stolb23 [73]

Answer:

I liked the video, it gave us lots of information about___. __ means/ is about.

Explanation:

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3 years ago

Does adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent, a lesser extent, or a greater e

igor_vitrenko [27]

Answer:

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em> by adding 1 mol of $C_06H_{12}O_6$ to 1 kg of water.

Explanation:

1) Moles of NaCl , $n_1=1 mol$

Mass of water = m= 1 kg = 1000 g

Moles of water = $n_2=\frac{1000 g}{18 g/mol}=55.55 mol$

Vapor pressure of the solution = $p$

Vapor pressure of the pure solvent that is water = $p_o=17.5 Torr$

Mole fraction of solute(NaCl)= $\chi_1=\frac{n_1}{n_1+n_2}$

$\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}$

$\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}$

$p=17.19 Torr$

The vapor pressure for the NaCl solution at 17.19 Torr.

2) Moles of sucrose , $n_1=1mol$

Mass of water = m = 1 kg = 1000 g

Moles of water = $n_2=\frac{1000 g}{18 g/mol}=55.55 mol$

Vapor pressure of the solution = $p'$

Vapor pressure of the pure solvent that is water = $p_o=17.5 Torr$

Mole fraction of solute ( glucose)= $\chi_1=\frac{n_1}{n_1+n_2}$

$\frac{p_o-p}{p_o}=\frac{n_1}{n_1+n_2}$

$\frac{17.5 Torr-p}{17.5 Torr}=\frac{1 mol}{1 mol+55.55 mol}$

$p'=17.19 Torr$

The vapor pressure for the glucose solution at 17.19 Torr.

p = p' = 17.19 Torr

Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent by adding 1 mol of $C_06H_{12}O_6$ to 1 kg of water.

3 0

3 years ago

You have 2.7 moles of carbon. How many atoms do you have?

Gelneren [198K]

Answer:

1.63 × 10²⁴ atoms.

Explanation:

To calculate the number of atoms (N) contained in 2.7moles of carbon, we multiply the number of moles (n) by Avogadro's number (6.02 × 10²³).

That is, N = n × nA

Where;

N = number of atoms

n = number of moles (mol)

nA = Avogadro's numbe

N = 2.7 × 6.02 × 10²³

N = 16.254 × 10²³

N = 1.63 × 10²⁴ atoms.

Hence, there are 1.63 × 10²⁴ atoms in 2.7moles of Carbon.

4 0

2 years ago

Consider the nuclear equation below.

Dovator [93]

Answer:

its NOT C

Explanation:

8 0

3 years ago

Read 2 more answers