Answer:
0.03g/mL
Explanation:
Given parameters include:
Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL
Dilution factor = 10-to-1
The absorbance at 595 nm was 0.78
Mass of the diluted sample = 0.015 mg
We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.
So, to determine the concentration of the diluted sample, we have:
concentration of diluted sample = 
=
(where ∝ was use in place of μ in the expressed fraction)
= 0.003 mg/μL
The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:
protein concentration of the original solution = 10 × concentration of the diluted sample.
= 10 × 0.003 mg/μL
= 0.03 mg/μL

= 0.03g/mL
Hence, the protein concentration of the original solution is known to be 0.03g/mL
The balanced reaction shows for every 2 Aluminum we need 3 Chloride gas.
20 Al * (3 Cl / 2 Al) = 30 Cl
We have 45 Cl ... Which is more than enough for 20 Al
We have excess Cl
Then the limiting reagent = Al
<u>Answer:</u>
NO ---> N +2 and O -2
<u>Explanation:</u>
Oxidation numbers are assigned to the elements of a compound to keep a track of the number of electrons each atom has.
Here we have a compound NO (Nitrogen Oxide). The Nitrogen is assigned an oxidation number of +2 while Oxygen in this compound is assigned an oxidation number of -2.
So the algebraic sum of the oxidation numbers of the elements in the compound NO is equal to zero.
Rojo, naranja, amarillo, verde, cian, azul y violeta
Answer:
Explanation:
percentage error = error x 100 / correct value
= (2.73 - 2.70) x100 / 2.70
= 1.11 %
The element is Aluminium whose density is 2.702 grams / cc
Boiling point of Aluminium = 2519⁰C .