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Arte-miy333 [17]
3 years ago
13

Consider the reaction between NiS2 and O2:

Chemistry
1 answer:
STatiana [176]3 years ago
3 0

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Dejanras

Ambitious

3.2K answers

30.3M people helped

m(NiS₂) = 11.2 g.

n(NiS₂) = m(NiS₂) ÷ M(NiS₂).

n(NiS₂) = 11.2 g ÷ 122.8 g/mol.

n(NiS₂) = 0.091 mol.

m(O₂) = 5.43 g.

n(O₂) = 5.43 g ÷ 32 g/mol.

n(O₂) = 0.17 mol; limiting reactant.

From chemical reaction: n(NiS₂) : n(O₂) = 2 : 5.

0.091 mol : n(O₂) = 2 : 5.

n(O₂) = 0.2275 mol, not enough.

n(NiO) = 4.89 g .

n(O₂) : n(NiS) = 5 : 2.

n(NiS) = 0.068 mol.

m(NiS) = 0.068 mol · 74.7 g/mol = 5.08 g.

percent yield = 4.89 g / 5.08 g · 100% = 96.2%.

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