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3 years ago

11

Aluminum oxide was prepared by heating 225 g of chromium (III) oxide with 125 g of aluminum. Calculate the percent yield of 100.

0 g of aluminum oxide were obtained

1 answer:

Veronika [31]3 years ago

4 0

Answer:

66.25%

Explanation:

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Humans have three types of cone cells in their eyes, which are responsible for color vision. Each type absorbs a certain part of

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Answer:

The frequency of this light is $6.98\times 10^{14} s^{-1}$ .

Explanation:

Wavelength of the light = $\lambda = 430 nm=4.30\times 10^{-7} m$

Speed of the light = c = $= 3\times 10^8 m/s$

Frequency of the light = $\nu$

$\nu =\frac{c}{\lambda }$

$\nu =\frac{3\times 10^8 m/s}{4.30\times 10^{-7} m}=6.98\times 10^{14} s^{-1}$

The frequency of this light is $6.98\times 10^{14} s^{-1}$ .

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3 years ago

Cells get energy from food to sustain the life of the organism.

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The answer is B hope this helped

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3 years ago

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Classify the following as a solution, suspension or colloid

frosja888 [35]

Answer:

Solution - (a) Brine . Suspension - (c) sand and water, (g) chalk and water Colloid - (e) air, (f) smoke , (d) soda , (b) milk

Explanation:

A solution is an homogeneous mixture of two or more compounds.

A suspension is a heterogeneous mixture of two or more compounds while a colloid is a homogeneous mixture of two or more compounds with suspended particles which do not settle.

So, under these definitions, the classifications are as follows-

Solution - (a) Brine .

Suspension - (c) sand and water, (g) chalk and water

Colloid - (e) air, (f) smoke , (d) soda , (b) milk

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3 years ago

In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of

BARSIC [14]

Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is tartaric acid

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL$

Putting values in above equation, we get:

$2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL$

$M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M$

0.0042 M is the molarity of tartaric acid in this sample of wine.

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3 years ago

Which is the solubility product expression for pbcl2(s)

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The answer is [Pb^2+][Cl-]^2

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