A student determines the density of an element to be 2.73 g/cm 3 . If the accepted value is 2.70 grams per cm 3 , what is the st
1 answer:
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Answer:
Explanation:
Hello,
In this case, the described chemical reaction is:
Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:
Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:
Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:
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Answer:
Explanation:
Density is found by dividing the mass by the volume.
The mass of the liquid is 12.7 grams.
We know that 15 mL of this liquid was added to a 50 mL graduated cylinder. Therefore, the volume is 15 mL. The 50 mL is not relevant, it only tells us about the graduated cylinder.
Substitute the values into the formula.
Divide.
Round to the nearest hundredth. The 6 in the tenth place tells us to round the 4 to a 5.
The density of the liquid is about 0.85 grams per milliliter and choice A is correct.