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Dmitry [639]
3 years ago
15

To the nearest unit, what is the perimeter of this pentagon?

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
7 0

Answer:

The perimeter of the pentagon is;

29 units

Step-by-step explanation:

Let A, B, C, D, and E represent the vertices of the pentagon

The "x" and "y" coordinates of the vertices of the pentagon are given as follows;

A(-6, 2), B(-2, -2), C(5, -2), D(5, 2), E(-2, 5)

The length of the sides between each pair of coordinates can be found using the following formula;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

Therefore, we have;

Length of segment AB = √((-2 - (2))² + (-2 - (-6))²) = 4·√2

Length of segment BC = √((-2 - (-2))² + (5 - (-2))²) = 7

Length of segment CD = √((5 - 5)² + (2 - (-2))²) = 4

Length of segment DE = √((5 - 2)² + (-2 - 5)²) = √58

Length of segment EA = √((5 - (2))² + (-2 - (-6))²) = 5

The length of the perimeter of the pentagon = 5+√58 + 4 + 7 + 4·√2 ≈ 29.2726273554 ≈ 29

The length of the perimeter of the pentagon ≈ 29.

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Step-by-step explanation:

p_1:~~y = x^2+2\\p_2:~~y = 3x^2+2\\ \\ V{p_1} = \Big(-\dfrac{b}{2a}, -\dfrac{\Delta}{4a}\Big) = \Big(-\dfrac{0}{2}, -\dfrac{0^2-4\cdot 2}{4}\Big) = \Big(0,2\Big) \\ \\ Vp_2 = \Big(x_V, -\dfrac{\Delta}{4a}\Big) = \Big(0, -\dfrac{0^2-4\cdot 3 \cdot 2}{4\cdot 3}\Big) = \Big(0,2\Big) \\ \\ \\ \text{The distance is }0,~~\text{Because the vertices are equal.}

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