As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
Answer:
The answers are,
-3, -7
-2, 4
0, 2
2, 8
3, 11
Step-by-step explanation:
You just plug in the domain values into the equation and solve for f(x), so your domain number is your x value and the y value(f(x) value) is the answer
Answer:
(6x-2) - (-x+5)
= 6x-2 +x -5
= 7x -7
if you're trying to solve for x, then look below
7x=7
x=1
1. 20 of 40 is 50% 20/40 = 1/2 1/2 = 50%
2. It is 20% because 600 is 20% of 3000
3. 40% of 30 = 12 50 = 15 10% = 3 (get it)
4, 40% of 65 = 26 50%= 32.5 (get it)
