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Natali [406]
2 years ago
14

Suppose that the probability that a person books a hotel using an online travel website is 0.68. For the questions that follow,

consider a sample of fifteen randomly selected people who recently booked a hotel. 6) What is the probability that exactly ten people out of fifteen people used an online travel website when they booked their hotel? Round to the nearest thousandth.
Mathematics
1 answer:
Lorico [155]2 years ago
8 0

Answer:

0.213 is the required probability.  

Step-by-step explanation:

We are given the following information:

We treat person booking from online travel website as a success.

P(Booking through online travel website) = 0.68

Then the number of people follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

P(exactly ten people out of fifteen people used an online travel website)

P(x = 10)\\\\= \binom{15}{10}(0.68)^{10}(1-0.68)^5 \\\\= 0.213

0.213 is the probability that exactly ten people out of fifteen people used an online travel website when they booked their hotel.

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Answer:

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Step-by-step explanation:

De acuerdo a la información dada, puedes plantear las siguientes ecuaciones:

x+y= 45 (1)

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Segundo, debes reemplazar (3) en (2):

7(45-y)-1y=19

315-7y-1y= 19

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Tercero, debes reemplazar el valor de y en (3) para encontrar x:

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