Question

Suppose that the probability that a person books a hotel using an online travel website is 0.68. For the questions that follow, consider a sample of fifteen randomly selected people who recently booked a hotel. 6) What is the probability that exactly ten people out of fifteen people used an online travel website when they booked their hotel? Round to the nearest thousandth.

Answer 1

Answer:

0.213 is the required probability.  

Step-by-step explanation:

We are given the following information:

We treat person booking from online travel website as a success.

P(Booking through online travel website) = 0.68

Then the number of people follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 15

P(exactly ten people out of fifteen people used an online travel website)

$P(x = 10)\\\\= \binom{15}{10}(0.68)^{10}(1-0.68)^5 \\\\= 0.213$

0.213 is the probability that exactly ten people out of fifteen people used an online travel website when they booked their hotel.