The real solutions the equation as given in the task content; x² = 225 are; +25 and -25.
<h3>What are the real solutions of the equation as given in the task content?</h3>
It follows from the task content that the real solutions of the equation as given in the task content can be determined as follows;
x² = 225
x = ± 15
Therefore, the real solutions of the equation are; +25 and -25.
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Answer:
ITS AN ASSESMENT THIS VIOLATES THE HONOR CODE
Step-by-step explanation:
To find a missing side of a right triangle use the Pythagorean theorem
A2+b2=c2
C is the hypotenuse (long side)
Plug into the equation
11^2+b2=12^2
121+b2=144
So subtract 144-121 to get the missing side you get 23
Take the square root
It will be 4.7
If they want it rounded
X=5
If I had any mistakes in my answer I am sorry but everything should be correct
6 is 75% of 8. 6/8 can be simplified to 3/4, which is easier to see as 75%.
When a linear equation is in the form y = mx + c, the c, or constant, is the intercept on the y axis, meaning it crosses the y axis at (0, 1).
The gradient (1/3 in this case) is how much the y increments (or decrements) per increase of 1 of the value of x.
This would mean that there would be one point at (0, 1), and another at (3, 2). Draw a line from these two points and beyond, and that is the graph sketched.
