Answer:
x = 4 ,y = -10
, z = -10
Step-by-step explanation:
Solve the following system:
{y + 4 = -6 | (equation 1)
16 - 3 y + 2 z = 26 | (equation 2)
Express the system in standard form:
{y+0 z = -10 | (equation 1)
-(3 y) + 2 z = 10 | (equation 2)
Swap equation 1 with equation 2:
{-(3 y) + 2 z = 10 | (equation 1)
y+0 z = -10 | (equation 2)
Add 1/3 × (equation 1) to equation 2:
{-(3 y) + 2 z = 10 | (equation 1)
0 y+(2 z)/3 = (-20)/3 | (equation 2)
Multiply equation 2 by 3/2:
{-(3 y) + 2 z = 10 | (equation 1)
0 y+z = -10 | (equation 2)
Subtract 2 × (equation 2) from equation 1:
{-(3 y)+0 z = 30 | (equation 1)
0 y+z = -10 | (equation 2)
Divide equation 1 by -3:
{y+0 z = -10 | (equation 1)
0 y+z = -10 | (equation 2)
Collect results:
Answer: y = -10
, z = -10
