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2 years ago

Helpp my grades are almost dueeeeeeee,,, but anyway hows yall dayyy?

Mathematics

2 answers:

natita [175]2 years ago

7 0

Answer: c) -1/6, check picture below

Step-by-step explanation:

tekilochka [14]2 years ago

3 0

C is the. Answer as you multiply by -1/3

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You bike for 2 hours at a speed no faster than 17.6 mph. Write an inequality that represents the possible number of miles you bi

Whitepunk [10]

Total no. of hours you spent biking = 2 hours
the speed at which you rode your bike ≤ 17.6 mph
Now,
We have,
$speed = \frac{distance}{time}$

$17.6 = \frac{distance}{2}$

$17.6 *2= distance$

$35.2=distance$

So, you for given conditions, you can't travel more then 35.3 miles

So, the inequality for the given circumstances is:
x ≤ 35.2

4 0

3 years ago

Read 2 more answers

A person sold an article at a profit of 15% if he sold it for Rs 81 less , his loss would have been 12% find the cost price of t

Misha Larkins [42]

Answer:

let cp be x

sp= 115x/100 ---(when 15%gain)

sp = 88x/100------(when 12% loss

according to question

115x/100 - 88x/100 = 81

or, (115x-88x)= 8100

or, 27x = 8100

or, x= 8100/27

x = 300

hence cp is RS 300

3 0

2 years ago

A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is

Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

$\Delta s = s_2-s_1$

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

$\Delta x = x_2-x_1$

So we can use the given points $P1:(x_1,y_2) \text{ and } P_2: (x_2,y_2)$ on the displacement formula

$\Delta x = 15-4\\\Delta x = 11$

In the same manner we can look at the y components of those points to find the vertical displacement

$\Delta y = 17-8\\\Delta y =9$

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

$\tan(\theta) = \cfrac{\Delta y}{\Delta x}$