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BigorU [14]
3 years ago
12

Three lines are described below. Write an equation in slope-intercept form for each line.

Mathematics
1 answer:
grigory [225]3 years ago
7 0

a. Equation in slope-intercept form of a line parallel to y = 2/5x +1 will be: y = 2/5x + 5

b. Equation in slope-intercept form of a line perpendicular to y = 2/5x +1 will be: y = -5/2x + 1

c.  Equation in slope-intercept form of a line that is neither parallel nor perpendicular to y = 2/5x +1 will be: y = 3x + 1

<h3>Slope-intercept Equation of Parallel and Perpendicular Lines</h3>
  • Slope-intercept equation, where b is the y-intercept and b m is the slope is represented as y = mx + b.
  • Equations of parallel lines have the same slope.
  • Equations of perpendicular lines will have slope that are negative reciprocal of each other.
  • If two lines are neither parallel nor perpendicular, their equation will have different slopes, and the slope of one is not the negative reciprocal of each other.

Therefore:

a. Equation in slope-intercept form of a line parallel to y = 2/5x +1 will be: y = 2/5x + 5

b. Equation in slope-intercept form of a line perpendicular to y = 2/5x +1 will be: y = -5/2x + 1

c.  Equation in slope-intercept form of a line that is neither parallel nor perpendicular to y = 2/5x +1 will be: y = 3x + 1

Learn more about slope-intercept form on:

brainly.com/question/25826868

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3 years ago
Question 7: Which of the following statements is true?
yawa3891 [41]

Problem 7)

The answer is choice B. Only graph 2 contains an Euler circuit.

-----------------

To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.

With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.

================================================

Problem 8)

The answer is choice B) 5

-----------------

Work Shown:

abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10

101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10

101 base 2 = (1*4 + 0*2 + 1*1) base 10

101 base 2 = (4 + 0 + 1) base 10

101 base 2 = 5 base 10


4 0
3 years ago
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