D. the centroid
i think so
Answer:
Prime
Step-by-step explanation:
- As there is no common between 5y and 7 except 1 as factor.
- Hence its not factorable
Hope this help you with this problem!
Answer:
<em>A) (-5,7)</em>
Step-by-step explanation:
<u>Functions and Relations</u>
A set of values A can have a relation with another set B as long as at least one element of A has at least one image in B. Functions are special relations where each element of A (the domain of the function) has one and only one image on B (the range of the function).
By looking at the options, we can see that x=9, x=-8, and x=-1 already have defined values in Y, so if we define another value for any of them the relation will stop being a function. The only possible choice to preserve the function is the option

Answer:
x=1 or x=−2 or x=−3
Step-by-step explanation:
x3+4x2+x−6=0
Step 1: Factor left side of equation.
(x−1)(x+2)(x+3)=0
Step 2: Set factors equal to 0.
x−1=0 or x+2=0 or x+3=0
x=1 or x=−2 or x=−3