Answer:
So basically anything higher than .5 would be x>.5 so it has to be greater than or equal to .51
Step-by-step explanation:
.51 .75 .89 .56 .78 .86 .61 it goes on and on as long as it is greater than .50
<h3>Given :-</h3>
- Pranav ran 20.3 km more than Branda
To find :
- No. of kilometers did Brenda run.
<h3>Let :</h3>
- No. of kilometers ran by Brenda be x.
<h3>Solution:</h3>
Equation formed:-
Total distance covered by Pravan = More distance covered by Pravan + distance covered by Brenda.
Therefore:-
Write the equation
When we transfer 20.3 to left side the positive sign (+) will change into negative sign (–)
Arrange the equation because x is always represented at left side.
After subtracting 38.6 with 20.3 we will get result as 18.3 .
ABC=50
DCE=65
DEF= I think 115
I hope that helps I would appreciate brainliest if possible :)
Area of the quarter sector
Area of the entire circle = pi * r^2
Area of the quarter circle = pi r^2 / 4
r = 9
Area of the quarter circle = pi 9^2 / 4
Area of the quarter circle = pi 81/4 = 20.25 pi
Area of the triangle
Area pf the triangle = 1/2 b*h
b = h = r
r = 9
Area of the triangle = 1/2 9 * 9
Area of teh triangle = 1/2 81
Area of the triangle = 40.5
Area of the shaded area
The shaded area = Area of the 1/4 circle - area of the triangle
The shaded area = (20.24 pi - 40.5)ft^2
A <<<<<< Answer.
