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pochemuha
2 years ago
15

If a box of cereal that is 12.5 ounces costs $2.78, what is the unit price? Round your answer to the nearest cent.

Mathematics
1 answer:
Reptile [31]2 years ago
5 0

Answer: A) $4.50 per ounce

Step-by-step explanation: All you do is divide 12.5 by 2.78. You should get 4.4964028777, which, when rounded up to the nearest cent, should equal $4.50

Hope you found this helpful!

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Step-by-step explanation:

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Sketch a graph to math this: The Olympic skier waited at the top of the mountain for 2 minutes before heading down the ski slope
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7 minutes

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A $120.00 pair of shoes at your nearby department store is marked up 4% and then is offered at 45% off. If sales tax is 13%, wha
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$26

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Find the roots of the parabola given by the following equation <br> 2x^2+5X-9=2x
natta225 [31]

Answer:

x=-3\:or\:x=\frac{3}{2}

Step-by-step explanation:

The given parabola has equation

2x^2+5x-9=2x

We rewrite in standard form to obtain:

2x^2+5x-2x-9=0

2x^2+3x-9=0

Split the middle terms to get:

2x^2+6x-3x-9=0

Factor by grouping:

2x(x+3)-3(x+3)=0

(x+3)(2x-3)=0

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7 0
3 years ago
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
3 years ago
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