Answer:
A) Quantity x minus 5 over quantity x plus 1, where x≠-1 and x≠-9
Step-by-step explanation:
Simplifying the numerator first:
x² + 4x - 45 using the quadratic formula you get;
(x - 5)(x + 9)
Then simplifying the denominator x² + 10x + 9 using a quadratic formula you get;
(x + 1)(x + 9)
Dividing the numerator and denominator now gives;
Cancelling (x + 9) throughout leaves you with;
The only restrictions here is if x = 1 and 9 which will give an undefined answer.
A bus holds 40 people and a van holds 10
<span>5x= 6x^2 -3
</span><span>6x^2 -5x -3
a = 6
b = -5
c = -3
x = [-b +- sq root(b^2 -4ac)] / 2a
x = [--5 +- </span><span>sq root (25 -(4*6*-3)] / 12
</span><span>x = [5 +- sq root (25 + 72)] / 12
x = [5 + sq root (97)] / 12
x = 5 +- </span><span>9.84886] / 12
x1 = </span><span><span><span>1.237405
</span>
</span>
</span>
<span>
x2 = </span><span><span><span>-0.404072
</span>
</span>
</span>
Answer:
3 games
Step-by-step explanation:
The computation of the maximum number of games that he could buy is shown below:
= Amount available - already spent
= $75 - $28
= $47
If each game cost $15
So, the maximum no of games is
= $47 ÷ $15
= 3.133
= 3 games
