Answer: Colligative properties are those properties of solutions that are dependent on the concentration of the solutes in the solution.
Colligative properties has to do with solutions, that is, solutes that are dissolved in solvents. Examples of colligative properties are: freezing point depression, vapour pressure lowering, boiling point elevation and osmotic pressure. Colligative properties do not depend on the identity of the solutes, this implies that the effect of colligative properties are uniform across all solutions. For example, the freezing point depression of any solution will depend on the concentration of solutes that are dissolve in solution.
Answer: place a 2 in front of NaNo3 on left side of equation while leaving the other blanks empty or you can place a 1 in those blanks
Explanation:
Step 1 count and write down the amount of each given element for both sides
Step 2 begin placing numbers (coefficients) to each side to balance
Hi,
The answer should be C.
Hope this helps, if you’d like further explanation please let me know.
Answer:
-36.67 KJ
Explanation:
Now, we ,must find the E°cell as follows;
E°cell= E°cathode - E°anode
E°cathode= -0.25 V
E°anode = - 0.44 V
E°cell= -0.25 -(- 0.44) = 0.19 V
Equation of the reaction; Ni2+ (aq) + Fe(s) → Ni(s) +Fe2+ (aq)
Hence, n=2, there were two electrons transferred.
ΔG=-nFE°cell
ΔG= -(2 * 96,500 * 0.19)
ΔG= -36670 J
ΔG= -36.67 KJ
