A system of equations is shown below y=3x-7 y=2x+1 what is the solution to the system of equations 8 ,17 -8,17 -8,-17 8,-17

Mathematics

1 answer:

Triss [41]2 years ago

6 0

Answer:

(8, 17)

Step-by-step explanation:

y = 3x - 7, y = 2x + 1

Substitute the second equation into the first for y.

2x + 1 = 3x - 7

8 = x

Now use 8 for x in one of the equations and solve for y.

2(8) + 1 = y

y = 17

(8, 17)

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3 years ago

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$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
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\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
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$

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\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4$

$\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
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3 years ago

Do anyone think this is right ?

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It is not true because there C and E are on different sides, if that makes sense (which means your answer is correct)

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