Answer:
1) 2.054 x 10⁻⁴ mol/L.
2) Decreasing the temperature will increase the solubilty of O₂ gas in water.
Explanation:
1) The solubility of O₂ gas in water:
- We cam calculate the solubility of O₂ in water using Henry's law: <em>Cgas = K P</em>,
- where, Cgas is the solubility if gas,
- K is henry's law constant (K for O₂ at 25 ̊C is 1.3 x 10⁻³ mol/l atm),
- P is the partial pressure of O₂ (P = 120 torr / 760 = 0.158 atm).
- Cgas = K P = (1.3 x 10⁻³ mol/l atm) (0.158 atm) = 2.054 x 10⁻⁴ mol/L.
2) The effect of decreasing temperature on the solubility O₂ gas in water:
- Decreasing the temperature will increase the solubilty of O₂ gas in water.
- When the temperature increases, the solubility of O₂ gas in water will decrease because the increase in T will increase the kinetic energy of gas particles and increase its motion that will break intermolecular bonds and escape from solution.
- Decreasing the temperature will increase the solubility of O₂ gas in water will because the kinetic energy of gas particles will decrease and limit its motion that can not break the intermolecular bonds and increase the solubility of O₂ gas.
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Carbon is used to reduce the oxide of aluminium to get the metal, in case condensation happens during this process.
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Hope this helps!
Answer:
True
Explanation:because of the motion
Answer:
D
Explanation:
We can use the mole ratio to calculate the partial pressure. The total number of moles is 0.2 + 0.2 + 0.1 = 0.5 moles
Now, we know that the mole fraction of the argon gas would be 0.2/0.5
The partial pressure is as follows. To calculate this, we simple multiply the number of moles by the total pressure.
0.2/0.5 * 5 = 1.0/0.5 = 2.00atm
D
Answer:
1200 mL
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 400 mL.
Initial pressure (P1) = 600 mmHg.
Final volume (V2) =..?
Final pressure (P2) = 200 mmHg
Step 2:
Determination of the final volume i.e the new volume of the gas.
Considering the question given, we understood that the temperature is constant. Therefore the gas is obeying Boyle's law. Using the Boyle's law equation, the new volume is obtained as follow:
P1V1 = P2V2
600 x 400 = 200 x V2
Divide both side by 200
V2 = (600 x 400) /200
V2 = 1200 mL
Therefore, the new volume of the gas is 1200 mL.
