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pychu [463]
2 years ago
9

Find the equation line through point (-4,15) and (4,-5)

Mathematics
1 answer:
Oduvanchick [21]2 years ago
8 0
Answer highlighted in blue. Hope this helps.
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Identify the surface with the given vector equation. r(u, v) = 2 sin(u) i + 5 cos(u) j + v k, 0 ≤ v ≤ 5 plane hyperbolic parabol
olchik [2.2K]
Note that this just produces three parametric equations:

x(u) = 2 \sin(u)
y(u) = 5 \cos(u)
z(v) = v

In the x-y plane, this is just he parametric equation for an ellipse (as a function of u). The z is simply a linear function. 

The surface is then an ellipse extruded along the z-axis. We get a elliptic cylinder.
6 0
3 years ago
Can you solve -3(y-5)=24
garri49 [273]

Answer:y=-3

Step-by-step explanation:yes firs multiply everything by -3 in parenthesies

Then you would subtract 15 from both sides

Next you would divide 9 by -3 and you would get -3

So y =-3

7 0
3 years ago
Read 2 more answers
Which of the following is equivalent to the equation below?
DerKrebs [107]
B is the correct answer R=Q-7s/4
6 0
3 years ago
Having a hard time with this
raketka [301]

Answer:

the correct answer is D

Step-by-step explanation:

because the -9 5/8 is in absolute value marks.

6 0
3 years ago
Solve this system of equations by
Goshia [24]
Answer: x = 12 and y = -8

Explanation:
x + y = 4
4x + 3y = 24
———————
-3(x + y = 4)
4x + 3y = 24
———————-
-3x - 3y = -12
4x + 3y = 24
———————
x = 12

If x = 12
x + y = 4
12 + y = 4
y = -8
6 0
1 year ago
Read 2 more answers
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