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ladessa [460]
3 years ago
15

How many parts are needed to prove triangles are congruent?

Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0
Two triangles are congruent if and only if they have the same three sides and the same three angles. That does not mean that the triangles are in the same position. If there is a turn or flip you can match these triangles to see that in fact they are congruent.

If the sides are the same, then the conclusion is that they are congruent, but this does not always work with angles, that is, t<span>wo triangles with the same angles </span><em>might be</em> congruent or <em>might no</em>t if they have different sizes <span>because, even though all angles match, </span>one side can be larger than the other<span>.</span>
JulijaS [17]3 years ago
5 0
You need three parts but they can’t all be angles
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3 years ago
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Tickets for a concert are $40 for main-floor seats and $25 for upper level seats. A total of 2000 concert tickets were sold. The
Tems11 [23]

Step-by-step explanation:

<u>to show how many tickets were sold:</u>

x = upper floor tickets

y = main floor tickets

x + y = 2000

<u>to show total amount of revenue:</u>

25x + 40y = 62,000

<u>Finding answer using both equations:</u>

x + y = 2000

multiply each side by 25

25x + 25y = 2000 × 25

25x + 25y = 50,000

25x + 40y = 62,000

-

25x + 25y = 50,000

-----------------------------------

15y = 12,000

^ this is column subtraction

<em>^ this column subtraction is done to isolate y so we can work with one value rather than 2</em>

15y = 12,000

divide each side by 15

12,000 ÷ 15 = 800

y = 800

x + y = 2000

x + 800 = 2000

x = 1200

Therefore 1200 upper-level tickets were sold

800 main floor tickets were sold

4 0
3 years ago
What does a markdown in math mean?
oee [108]
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Qhat is the ratio of 6to 5​
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For each of the following functions, (i) find the constant c so that f(x) is a pdf of a random variable X, (ii) find the cdf, F(
mel-nik [20]

Answer:

(a)

c=1/2

cdf  is    F(x) = x^2

Step-by-step explanation:

Remember that if   f  is the pdf of a random variable X .

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Then,

(a)

\int\limits_{-\infty}^{\infty}  4xc \,dx = \int\limits_{0}^{1}  4xc \, d x = 2c = 1

Therefore

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and

 f(x)=2x

then to compute the cdf, we have

F(x) = P(X \leq x) = \int\limits_{-\infty}^{x}   2y \,dy  =  \int\limits_{0}^{x}   2y \, dy =  x^2

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