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ladessa [460]
3 years ago
15

How many parts are needed to prove triangles are congruent?

Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0
Two triangles are congruent if and only if they have the same three sides and the same three angles. That does not mean that the triangles are in the same position. If there is a turn or flip you can match these triangles to see that in fact they are congruent.

If the sides are the same, then the conclusion is that they are congruent, but this does not always work with angles, that is, t<span>wo triangles with the same angles </span><em>might be</em> congruent or <em>might no</em>t if they have different sizes <span>because, even though all angles match, </span>one side can be larger than the other<span>.</span>
JulijaS [17]3 years ago
5 0
You need three parts but they can’t all be angles
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Answer:

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Step-by-step explanation:

Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>

<em>=  >  \angle RPQ +  \angle PQR =  \angle NRQ \\  \\  =  > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\  \\  =  > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\  \\  =  > 49\degree  + 5 \degree= 15x\degree - 6x\degree \\  \\  =  > 54\degree = 9x\degree \\  \\  =  > 9x\degree = 54\degree \\  \\  =  > x\degree =  (\frac{54}{9} )\degree \\  \\  =  > x\degree = 6\degree \\  \\ Putting \: value \: of \: x \: in \:  \angle NRQ  \\   \\  =  > \angle NRQ = (15x - 5)\degree \\  \\  =  >  \angle NRQ = (15 \times 6 - 5) \degree \\  \\  =  >  \angle NRQ =85 \degree</em>

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