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Slav-nsk [51]
3 years ago
6

The graph of a linear equation passes through (0, 5) and (-10, 0). What is the equation?​

Mathematics
1 answer:
anzhelika [568]3 years ago
8 0

(\stackrel{x_1}{0}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-10}~,~\stackrel{y_2}{0}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{0}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{-10}-\underset{x_1}{0}}}\implies \cfrac{-5}{-10}\cfrac{1}{2}

\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{5}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{0}) \\\\\\ y-5-\cfrac{1}{2}x\implies y=\cfrac{1}{2}x+5

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A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. A st
Anon25 [30]

Answer:

(a) The probability that a randomly selected U.S. adult uses social media is 0.35.

(b) The probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c) The probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = an US adult who does not uses social media.

<em>Y</em> = an US adult between the ages 18 and 29.

<em>Z</em> = an US adult between the ages 30 and above.

The information provided is:

P (X) = 0.35

P (Z) = 0.78

P (Y ∪ X') = 0.672

(a)

Compute the probability that a randomly selected U.S. adult uses social media as follows:

P (US adult uses social media (<em>X'</em><em>)</em>) = 1 - P (US adult so not use social media)

                                                   =1-P(X)\\=1-0.35\\=0.65

Thus, the probability that a randomly selected U.S. adult uses social media is 0.35.

(b)

Compute the probability that a randomly selected U.S. adult is aged 18–29 as follows:

P (Adults between 18 - 29 (<em>Y</em>)) = 1 - P (Adults 30 or above)

                                            =1-P(Z)\\=1-0.78\\=0.22

Thus, the probability that a randomly selected U.S. adult is aged 18–29 is 0.22.

(c)

Compute the probability that a randomly selected U.S. adult is 18–29 and a user of social media as follows:

P (Y ∩ X') = P (Y) + P (X') - P (Y ∪ X')

                =0.22+0.65-0.672\\=0.198

Thus, the probability that a randomly selected U.S. adult is 18–29 and a user of social media is 0.198.

6 0
3 years ago
Chandler, Jamal, Allison, and Qi are given the following problem. In 1982, Wayne Gretsky set a record for the greatest number of
Pavel [41]

Answer:

The correct answer is B.

Step-by-step explanation:

Since Chandler, Jamal, Allison, and Qi are given the following problem: "In 1982, Wayne Gretsky set a record for the greatest number of hockey goals in one season with 92 goals. If a player has scored 60 goals this season and averages 2 goals per game, how many additional games must he play to break the record? ", And each student writes an inequality to represent the situation:

Chandler wrote 60 + 2g ≥ 92

Jamal wrote 60 + 2g> 92

Allison wrote 60 + 2g <92

Qi wrote 60 + 2g ≤ 92

To determine whose inequality is correct, the following calculation must be performed:

92 - 60 = 32

32/2 = 16

Chandler: 60 + 2x16 ≥ 92

Thus, Chandler wrote the correct option.

6 0
2 years ago
Felix has $50 in a savings account that earns 5% interest, compounded annually. To the nearest cent, how much interest will he e
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Answer:

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Step-by-step explanation:

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<em>We do this step twice because the interest is for </em><em>2 years.</em>

52.5 * 1.05 = 55.125

<em>This rounds up to 55.13, your final answer!</em>

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8 0
3 years ago
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