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MissTica
2 years ago
12

In several activities you saw that light was scattered, transmitted, absorbed, or some combination of these. In the activity wit

h the clear and colored water, you saw that the more light that was absorbed, the less that was scattered and transmitted. Is this relationship true for the object your teacher just showed you? Make a general rule about the way the amounts of light reflected or scattered, transmitted, and absorbed by any object are related to each other.
Physics
1 answer:
Romashka-Z-Leto [24]2 years ago
6 0

Answer:

Summary

In a hands-on way, students explore light's properties of absorption, reflection, transmission and refraction through various experimental stations within the classroom. To understand absorption, reflection and transmission, they shine flashlights on a number of provided objects. To understand refraction, students create indoor rainbows. An understanding of the fundamental properties of light is essential to designing an invisible laser security system, the ongoing objective in this unit.

This engineering curriculum aligns to Next Generation Science Standards (NGSS).

Enhanced photo shows a very bright rainbow against a dark gray sky.

Students explore light

copyright

Engineering Connection

In designing laser-based security systems, engineers consider the implications of the penetrating properties of electromagnetic radiation. The concepts of wave absorption and transmission are fundamental in the design of laser based security systems, and have additional applications in biomedical engineering. In x-ray imaging, various tissue types result in a range of transmittances that can be recorded to depict bones on x-ray film. Engineers must also be aware of safety concerns; even low doses of high-energy radiation can be dangerous, especially in the case of gamma radiation. For cancer radiation treatments, control of high-energy radiation can be beneficial, but must be carefully managed. Students consider the potential real-world uses of various types of radiation in questions 2 and 5-9 of the post-activity assessment handout.

Learning Objectives

After this activity, students should be able to:

Explain the properties of light as related to security systems.

Describe which objects reflect, absorb or transmit light.

Explain light refraction as applied to rainbows that appear in nature.

Identify a number of applications of radiation to science and technology today.

This activity also meets the following Tennessee Foundations of Technology educational technology content standards: 2.0, 3.0, 4.0, 5.0, 6.0, 7.0 and 8.0.

This activity also meets the following National Science Education Standards (NSES) teaching standards: A, B, C, D, E, F; see

Explanation:

correct me if I'm wrong:)

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Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.
vagabundo [1.1K]

Answer:

R_total = 14.57 Ω ,  V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance  

         R_{eq} = ∑ R_{i}

* For resistance in parallel

        1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

         R_B = Rb + R4

         R_B = 2 + 18

         R_B = 20 Ω

Branch C

         R_C5 = Rc + R5

         R_C5 = 3 + 12

         R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

         1 / R_BC = 1 / R_B + 1 / R_C5

          1 / R_BC = 1/20 + 1/15 = 0.116666

          R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

          R_total = R_A + R_BC

          R_total = 6 + 8.57

          R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

           10 = V_a + V_BC

           10 = i R_a + i R_BC = i (R_a + R_BC)

           i = 10 / (R_a + R_BC)

           i = 10 / (14.57)

           i = 0.6863 A

The current in the series circuit is constant

          V_BC = i R_BC

          V_BC = 0.6863 8.57

          V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

     Branch C

             V_BC = i R_C5

             i = V_BC / R_C5

             i = 5.8819 / 15

             i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

             V_C = i R_C

              V_C = 0.39213 3

              V_C = 1.176 V

3 0
3 years ago
A portable CD player uses two 1.5 volt batteries. if the current in the CD player is 2amps ,what is resistance?
chubhunter [2.5K]

resistance=voltage/current

1.5/2=0.75ohms

7 0
3 years ago
A model train traveling at a constant speed around a circular track has a constant velocity
Mrac [35]
The answer should be yes
7 0
3 years ago
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4. During which three months is the difference the same between average high temperature and average low temperature?
kkurt [141]

Answer:

1 Inch and 20 F

Explanation:

6 0
3 years ago
If an object accelerates from rest, with a constant of 8 m/s2, what will its velocity be after 35s?
AlladinOne [14]

Answer:

<em>Its speed will be 280 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the speed of an object changes by an equal amount in every equal period of time.

If a is the constant acceleration, vo the initial speed, vf the final speed, and t the time, vf can be calculated as:

v_f=v_o+at

The object accelerates from rest (vo=0) at a constant acceleration of a=8\ m/s^2. The final speed at t=35 seconds is:

v_f=0+8*35

v_f=280\ m/s

Its speed will be 280 m/s

5 0
2 years ago
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