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lawyer [7]
3 years ago
6

A parachute on a racing dragster opens and changes the speed of the car from 95 m/s to 35 m/s in a period of 6.5 seconds. What i

s the acceleration of the dragster? ​
Physics
1 answer:
tatiyna3 years ago
6 0

Answer:

30 miles

Explanation:

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What is the acceleration of a 4,000 kg car pushed with a<br> force of 12,000 N?
jek_recluse [69]

Answer:

3 m/s

Explanation:

A= F/m

12,000/ 4000 = 3

8 0
2 years ago
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How fast would a 2-kilogram object need to move to have the same kinetic
siniylev [52]

Answer:

11.3 m/s

Explanation:

KE₁ = KE₂

½m₁v₁² = ½m₂v₂²

½ (2 kg) v² = ½ (4 kg) (8 m/s)²

v ≈ 11.3 m/s

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2 years ago
A 5000kg freight car moving at 2 m/s East collides with a 10,000kg freight car at rest. Upon collision, they got stuck and moved
mr_godi [17]

Answer:

A

Explanation:

6 0
2 years ago
Why does the density of a substance remain the same for different amounts of the substance
Novay_Z [31]
The molarity remains the same so the ratio does not change
5 0
3 years ago
A skier leaves the horizontal end of a ramp with a velocity of 31.0 m/s and lands 156.3 m from the base of a ramp how high is th
BartSMP [9]

<u>Answer:</u>

The height of ramp = 124.694 m

<u>Explanation:</u>

Using second equation of motion,

s = ut + \frac{1}{2}at^2

From the question,

u = 31 m/s; s = 156.3 m, a=0

substituting values

156.3 = 31\times t + 0

t = \frac{156.3}{31 }

= 5.042 s

Similary, for the case of landing

t = 5.042 s; initial velocity, u =0

acceleration = acceleration due to gravity, g = 9.81 m/s^2

Substituting in h = ut + \frac{1}{2}gt^2

h = 0 + \frac{1}{2} \times 9.81 \times (5.042)^2

h = 124.694 m

So height of ramp = 124.694 m

3 0
3 years ago
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