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prisoha [69]
2 years ago
15

In a light wave, which properties tell you the color of light?

Physics
1 answer:
Alenkasestr [34]2 years ago
5 0

<em><u>Answer </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>In</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>prop</u></em><em><u>erty</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>tells</u></em><em><u> </u></em><em><u>about</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>col</u></em><em><u>or</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>it</u></em><em><u>'s</u></em><em><u> </u></em><em><u>Wavel</u></em><em><u>ength</u></em><em><u> </u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em>

<em><u>Wavel</u></em><em><u>ength</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>distan</u></em><em><u>ce</u></em><em><u> between</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>crest</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>through</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>also</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>dist</u></em><em><u>ance</u></em><em><u> </u></em><em><u>after</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>repe</u></em><em><u>at</u></em><em><u> </u></em><em><u>its</u></em><em><u>elf</u></em><em><u> </u></em><em><u>!</u></em>

<em><u>It's</u></em><em><u> </u></em><em><u>SI</u></em><em><u> </u></em><em><u>unit</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>meter</u></em><em><u> </u></em><em><u>!</u></em><em><u> </u></em>

<em><u>It</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>scalar</u></em><em><u> </u></em><em><u>quan</u></em><em><u>tity</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>

<em><u>Diff</u></em><em><u>erent</u></em><em><u> </u></em><em><u>Wavelength</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>diff</u></em><em><u>erent</u></em><em><u> </u></em><em><u>col</u></em><em><u>or</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

<h2>• VIBGYOR </h2>

i.e, Violent , Indigo , Blue , Green , Yellow Orange, and Red along with their shades are the colors which we can see !!

• They almost range from 400nm to 700nm ( visible range of light )

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Many people drink 2 cans of coke each day. If each can has 39 grams of sugar, how many pounds of sugar is consumed each week? Gi
trasher [3.6K]

Answer:

1.20372

Explanation: start with 39 times 2 for how much grams each day and then multiply that by 7 then the convert grams into pounds

5 0
3 years ago
A cadillac escalade has a mass of 2 569.6 kg, if it accelerate at 4.65m/s2 what is the net force of the car
anygoal [31]
Force is equal to mass multiplied by acceleration, therefore 
F=ma
m=2569.6 kg
a=4.65m/s^2
therefore F=2569.6*4.65=11948.6 (correct to 1 d.p.)
3 0
3 years ago
You decide to visit Santa Claus at the north pole to put in a good word about your splendid behavior throughout the year. While
Fynjy0 [20]

Answer:

Explanation:

The question here is that if sneezy hands from a similar rope while delivering presents at the earth's equator, what will be the tension in the rope be. Here is the solution:The tension on the rope when it is at pole, T= 455 NTo find, the tension, t= mgTo solve for mass, m= t/g. Substituting this we have, m=455/9.8. m=46.43 kgAssume that the downwards acceleration is, a= -46.43 m/s^2.T = mg + maT = (46.43 kg) ( 9.8 m/s^2) - (46.43 kg) (-46.43 m/s^2)T = 455.01 kg-m/s^2 - -2155.74 kg-m/s^2T = 2610.75 kg-m/s^2 = 2610.75 N

3 0
2 years ago
The answer is 4 but idk how to get it so can somebody please explain how to get it
klemol [59]
How much gravitational potential energy does the block have
when it gets to the top of the ramp ?

      (weight) x (height) = (15 N) x (0.2 m)  =  3 Joules .

If there were no friction, you would only need to do 3 Joules of work
to lift the block from the bottom to the top.

But the question says you actually have to do 4 Joules of work
to get the job done.

Friction stole one of your Joules along the way.

Choice-4 is not the correct one.
Choice-1 is the correct one.

===========================

Notice that the mass of the block is NOT  15 kg , and you
don't have to worry about gravity to answer this question.

The formula for potential energy is  (m)·(g)·(h) .
But (m·g) is just the WEIGHT, and the formula
is actually (weight)·(height).
The question GIVES us the weight of the block . . . 15 N .
So the potential energy at the top is just (15N)·(0.2m) = 3 Joules.
3 0
3 years ago
Two ropes are attached to a 40-kg object. The first rope applies a force of 50 N and the second, 40 N. If the two ropes are perp
Montano1993 [528]

To solve this problem we will use the concepts related to the resulting Vector Force product of two components, that is,

|\vec{F}| = \sqrt{F_x^2+F_y^2}

If we take the Force of 50 N as the force in the X direction and the Force of 40 N in the Y direction we will have to:

|\vec{F}| = \sqrt{F_x^2+F_y^2}

|\vec{F}| = \sqrt{(50)^2+(40)^2}

|\vec{F}| = 64.03N

Finally, since Newton's second law, acceleration can be determined as

F = ma

a = \frac{F}{m}

a = \frac{ 64.03}{40}

a = 1.6m/s^2

Therefore the resultant magnitude of the acceleration of the object is 1.6m/s^2

4 0
3 years ago
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