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prisoha [69]
3 years ago
15

In a light wave, which properties tell you the color of light?

Physics
1 answer:
Alenkasestr [34]3 years ago
5 0

<em><u>Answer </u></em><em><u>:</u></em><em><u>-</u></em><em><u> </u></em><em><u> </u></em><em><u>In</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>prop</u></em><em><u>erty</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>tells</u></em><em><u> </u></em><em><u>about</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>col</u></em><em><u>or</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>it</u></em><em><u>'s</u></em><em><u> </u></em><em><u>Wavel</u></em><em><u>ength</u></em><em><u> </u></em><em><u>.</u></em><em><u> </u></em><em><u> </u></em>

<em><u>Wavel</u></em><em><u>ength</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>distan</u></em><em><u>ce</u></em><em><u> between</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>crest</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>one</u></em><em><u> </u></em><em><u>through</u></em><em><u> </u></em><em><u>,</u></em><em><u> </u></em><em><u>also</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>dist</u></em><em><u>ance</u></em><em><u> </u></em><em><u>after</u></em><em><u> </u></em><em><u>which</u></em><em><u> </u></em><em><u>the</u></em><em><u> </u></em><em><u>wave</u></em><em><u> </u></em><em><u>repe</u></em><em><u>at</u></em><em><u> </u></em><em><u>its</u></em><em><u>elf</u></em><em><u> </u></em><em><u>!</u></em>

<em><u>It's</u></em><em><u> </u></em><em><u>SI</u></em><em><u> </u></em><em><u>unit</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>meter</u></em><em><u> </u></em><em><u>!</u></em><em><u> </u></em>

<em><u>It</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>scalar</u></em><em><u> </u></em><em><u>quan</u></em><em><u>tity</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em><em><u> </u></em>

<em><u>Diff</u></em><em><u>erent</u></em><em><u> </u></em><em><u>Wavelength</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>light</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>diff</u></em><em><u>erent</u></em><em><u> </u></em><em><u>col</u></em><em><u>or</u></em><em><u> </u></em><em><u>!</u></em><em><u>!</u></em>

<h2>• VIBGYOR </h2>

i.e, Violent , Indigo , Blue , Green , Yellow Orange, and Red along with their shades are the colors which we can see !!

• They almost range from 400nm to 700nm ( visible range of light )

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What is the total resistance in this circuit?
VikaD [51]
Try 40. it seems correct. i’m sorry if i’m wrong.
6 0
3 years ago
A spring stretches 3.5 cm when a 9 g object is hung from it. The object is replaced with a block of mass 26 g which oscillates i
evablogger [386]

Answer:

The period of motion  of new mass T = 0.637 sec

Explanation:

Given data

Mass of object (m) = 9 gm = 0.009 kg

Δx = 3.5 cm = 0.035 m

We know that spring force is given by

F = m g

F = 0.009 × 9.81 = 0.08829 N

Spring constant

k = \frac{F}{x}

k = \frac{0.08829}{0.035}

k = 2.522 \frac{N}{m}

New mass(m_1) = 26 gm = 0.026 kg

Now the period of motion is given by

T = 2 \pi \sqrt{\frac{m}{k} }

T = 2 \pi \sqrt{\frac{0.026}{2.522} }

T = 0.637 sec

This is the period of motion  of new mass.

3 0
3 years ago
Four particles are in a 2-d plane with masses, x- and y- positions, and x- and y- velocities as given in the table below: what i
Arte-miy333 [17]
I attached the picture of the missing table.
Center of mass is the point such that if you apply force to it, the system would move without rotating.
We can use following formula to calculate the center of mass:
R=\frac{1}{M}\sum_{i=1}^{n=i}m_ir_i
Where M is the sum of the masses of all particles.
Part 1
To calculate the x coordinate of the center of mass we will use this formula:
R_x=\frac{1}{M}\sum_{i=1}^{n=i}m_ix_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
R_x=0.96m
Part 2
To calculate the y coordinate of the center of mass we will use this formula:
R_y=\frac{1}{M}\sum_{i=1}^{n=i}m_iy_i
I will do all the calculations in the google sheet that I will share with you.
For the x coordinate of the center of mass we get:
R_y=-0.84m
Part 3
We will calculate speed along x and y-axis separately and then will add them together.
v_x=\frac{\sum_{i=1}^{n=i}m_iv_x_i}{M}
v_y=\frac{\sum_{i=1}^{n=i}m_iv_y_i}{M}
Total velocity is:
v=\sqrt{v_x^2+v_y^2}
Once we calculate velocities we get:
v_x=-1.08\frac{m}{s}\\ v_y=-0.03\frac{m}{s}\\ v=\sqrt{(-1.08)^2+(-0.03)^2}=1.08\frac{m}{s}
Part 4
Because origin is left to our center of mass(please see the attached picture) placing fifth mass in the origin would move the center of mass to the left along the x-axis.
Part 5
If you place fifth mass in the center of the mass nothing would change. The center of mass would stay in the same place.
Here is the link to the spreadsheet:
https://docs.google.com/spreadsheets/d/1SkQHbI1BxiJnwpWbLmP0XWgcNPrGquH1K2MfN6cznVo/edit?usp=sharing

3 0
3 years ago
What is formed when 2 or more elements combine chemically
ira [324]

Answer:

compound

Explanation:

a substance made from two or more different elements that have been chemically joined. Examples of compounds include water (H2O), which is made from the elements hydrogen and oxygen, and table salt (NaCl), which is made from the elements sodium and chloride.

6 0
2 years ago
An advertisement claims that a particular automobile can "stop on a dime". What net force would actually be necessary to stop an
Luba_88 [7]

Answer:

F = 4399 KN

Explanation:

given,

mass of automobile = 890 kg

initial speed = 48 km/h

                     = 48 × 0.278 = 13.34 m/s

using equation of motion

v² = u² + 2 a × s

0 = 13.34² - 2 a ×0.018

a = \dfrac{13.34^2}{0.036}

a = 4943.21 m/s²

F   = m × a

F   = 890 × 4943.21

F   =  4399456.9 N

F = 4399 KN

hence, the  Net force is F = 4399 KN

4 0
3 years ago
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