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Ipatiy [6.2K]
3 years ago
8

A small jar of mustard holds 75% as much as a large jar of mustard. If the large jar holds 36 ounces, how much does the small ja

r hold?
Mathematics
1 answer:
SashulF [63]3 years ago
7 0

Answer:

27 ounces

Step-by-step explanation:

36 / 4 = 9 x 3 = 27

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Need help asap!!!
antiseptic1488 [7]

Answer:

there is no solution

Step-by-step explanation:

y + 7 = 3x

6x - 2y = 6    which can be simplied to be 3x - y = 6  (divide by 2)

let y = 3x - 7

substitute:  3x -(3x - 7) = 6

                  3x - 3x + 7 = 6

                              7 ≠ 6  therefore, no solution

8 0
3 years ago
How many integers less than 50 have exactly 2 distinct prime factors?
Vedmedyk [2.9K]

1, 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47

So 16 integers.

6 0
3 years ago
3. What is the radius of a circle whose area is 64π cm squared?
nataly862011 [7]

Answer:

Area = 64π

Area \: = \pi {r}^{2}Area=πr

2

64 \: \pi \: = \pi {r}^{2}64π=πr

2

{r}^{2} = \dfrac{64\pi}{\pi}r

2

=

π

64π

{r}^{2} = 64r

2

=64

r \: = \: \sqrt{64} = 8r=

64

=8

Radius = 8 units

Finding the Diameter -

Diameter = Radius x 2 = 8 x 2 = 16 .

\bold{Diameter \: is \: 16 \: units}Diameteris16units

8 0
3 years ago
Prove the polynomial identity. (2x−1)2+2(2x−1)=(2x+1)(2x−1) Drag and drop the expressions to correctly complete the proof of the
Alex_Xolod [135]

Answer:

Step-by-step explanation:

Given expression is,

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

To prove this identity we will take the left hand side of the equation and will prove equal to the right side.

(2x - 1)² + 2(2x - 1) = (2x - 1)(2x + 1)

4x² - 4x + 1 + 4x - 2 = (2x - 1)(2x + 1)

4x² - 1 = (2x - 1)(2x + 1)

(2x - 1)(2x + 1) = (2x - 1)(2x + 1) [Since a² - b² = (a - b)(a + b)]

6 0
4 years ago
What are the steps you would take to find the area of
kodGreya [7K]

Answer: Identify the shapes you will need to determine the area of the figure.

Calculate and add the areas of the unshaded triangle and two circles.

Step-by-step explanation:

3 0
4 years ago
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