All categories

3 years ago

When water is solid, do molecules move?

Chemistry

2 answers:

BabaBlast [244]3 years ago

8 0

Answer:

Ice is water in its solid form. Ice keeps its shape, even if it's removed from the container. The molecules in ice are locked into place and cannot move or slide past one another, but they do vibrate a little bit.

Explanation:

As the temperature drops or decreases, the water molecules gradually slow down. Eventually they stop moving and simply vibrate back and forth. At this point ice is formed, the solid phase of water. If the temperature is allowed to increase, the molecules will once again begin to vibrate faster and faster.

Lerok [7]3 years ago

8 0

Answer:Ice is water in its solid form. Ice keeps its shape, even if it's removed from the container. The molecules in ice are locked into place and cannot move or slide past one another, but they do vibrate a little bit.

Explanation:

You might be interested in

A sample contains 0.1895 g of salt per 50 g of seawater. What is its salinity?

Naily [24]

Use the rule of 3 simple
50 g mean 100% 0,1895 mean x% cross multiplie and calcule the x value x = 0,1895*100/50 = ?%

7 0

3 years ago

A red car and a blue car collide. What would be an example of Locard's exchange principle in this situation?

Lelu [443]

Answer:

The blue car left paint on the red car

Explanation:

8 0

3 years ago

Following reactions<br>FeSO4+KOH<br>

prohojiy [21]

Explanation:

$FeSO _{4} + \: KOH \: →K _{2}SO _{4} \: + \: Fe(OH) _{2}$

5 0

3 years ago

Where y and x are concentrations of the peptide in the extract and raffinate, respectively in g/L. It is desired to extract at l

zubka84 [21]

Answer:

sadjf akasj fk a

sadkf

ldj

a d i

i d o n t k n o w

Explanation:

6 0

3 years ago

In an aqueous solution of a certain acid the acid is 4.4% dissociated and the pH is 3.03. Calculate the acid dissociation consta

NeX [460]

Answer:

4.1x10⁻⁵

Explanation:

The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:

HA ⇄ H⁺ + A⁻

So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:

% = (dissociated/total)*100%

4.4% = (x/[HA])*100%

But x = [A⁻], so:

[A⁻]/[HA] = 0.044

The pH of the acid can be calcualted by the Handersson-Halsebach equation:

pH = pKa + log[A⁻]/[HA]

3.03 = pKa + log 0.044

pKa = 3.03 - log 0.044

pKa = 4.39

pKa = -logKa

logKa = -pKa

Ka = $10^{-pKa}$

Ka = $10^{-4.39}$

Ka = 4.1x10⁻⁵

4 0

3 years ago