Answer:
No solution is posible from the information provided
Step-by-step explanation:
Answer:to find the equivalent positive angle of a negative angle, just add 360 to it until it becomes positive and is between 0 and 360 degrees. -110 + 360 = 250. 250 degree angle and -110 degree angle are coterminal
Step-by-step explanation:to find the equivalent positive angle of a negative angle, just add 360 to it until it becomes positive and is between 0 and 360 degrees. -110 + 360 = 250. 250 degree angle and -110 degree angle are coterminal
Simplify the following:
(k^3 k^7)/3 - 5
Combine powers. (k^3 k^7)/3 = k^(7 + 3)/3:
k^(7 + 3)/3 - 5
7 + 3 = 10:
k^10/3 - 5
Put each term in k^10/3 - 5 over the common denominator 3: k^10/3 - 5 = k^10/3 - 15/3:
k^10/3 - 15/3
k^10/3 - 15/3 = (k^10 - 15)/3:
Answer: (k^10 - 15)/3
Answer:
wouldn't that just be -35?
Step-by-step explanation:
you just have to do -29-6
Answer:
![y - Q = - \frac{1}{4}(x - P)](https://tex.z-dn.net/?f=y%20-%20Q%20%3D%20%20-%20%20%5Cfrac%7B1%7D%7B4%7D%28x%20-%20P%29)
Step-by-step explanation:
Line g passes through (-2,6) and (-3,2).
The slope of line g is given by:
![\frac{ y_2-y_1}{x_2-x_1}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%20y_2-y_1%7D%7Bx_2-x_1%7D%20)
Let's substitute the values to get:
![\frac{2 - 6}{ - 3 - - 2}= \frac{ - 4}{ - 1} = 4](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%20-%206%7D%7B%20-%203%20-%20%20-%202%7D%3D%20%5Cfrac%7B%20-%204%7D%7B%20-%201%7D%20%20%3D%204)
The equation that is perpendicular to line g will have a slope that is the negative reciprocal of 4.
i.e -1/4
If this line passes through (P,Q), then the equation is:
![y - Q = - \frac{1}{4} (x - P)](https://tex.z-dn.net/?f=y%20-%20Q%20%3D%20%20-%20%5Cfrac%7B1%7D%7B4%7D%20%28x%20-%20P%29)