188m - 556m is the wavelength range for AM radio.
2.77 - 3.40m is the wavelength range for FM radio.
1) For AM radio
f(max) = 1600 × 10³ Hz
f(min) = 540 ×10³Hz
c = fλ
λ = c/f where,
c = speed of light
f = frequency
λ= wavelength
So,
λ(min) = 3 × 
/ 1600 × 10³ = 188 m
λ(max) = 3 × 10⁸/540 ×10³ = 556 m
So wavelength range of AM radio is 188 m - 556m
2) For FM radio
f(max) = 108 × 10⁶ Hz
f(min) = 88 × 10⁶ Hz
λ(min) = 3 × 10⁸ / 108 × 10⁶ = 2.77 m
λ(max) = 3 × 10⁸ / 88 × 10⁶ = 3.40 m
So wavelength range of FM radio is 2.77m - 3.40m
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Answer:
Explanation:
Given that a centripetal force is a form of force that gives rise or causes a body to move in a curved path.
Hence;
1. When a car is being driven around a track, it is the FORCE OF FRICTION that is acting upon the turned wheels of the vehicle, which transforms into the centripetal force required for circular motion.
2. When a ball being is swung on the end of a string, TENSION FORCE acts upon the ball, which transforms the centripetal force required for circular motion.
3. When the moon is orbiting the earth, it is the FORCE OF GRAVITY acting upon the moon, which transforms the centripetal force required for circular motion.
4. A rotating wheel on the other hand has NO centripetal force because centripetal force is pull towards the center of a motion. However the speed of the object is tangent to the circle, while the direction of the force is also perpendicular to the direction of the rotating wheel.
Answer:
The acceleration is 10 m/s²
Explanation:
The question seeks to show the relationship between force, mass and acceleration. Hence, the formula to be used here is that of force which is shown below
F = ma
where F is the force (800 N)
m is the mass (80 kg)
a is the acceleration (unknown)
From the formula above (Force = mass multiplied by acceleration)
800 N = 80 kg × a
a = 800 ÷ 80
a = 10 m/s²
Answer:
0.5 M = 1 second. =. 1.0 M= 2 seconds
Explanation:
for every 0.5 of a meter you add a second
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Below are the choices and the answer is <span>B.
</span>a.) Models can be changed by scientists who are more famous than previous scientists.
<span>b.) As technology advances, new experiments often expose problems in accepted theories. </span>
<span>c.) Scientists tend to value new theories because they are more exciting. </span>
<span>d.) A newer theory is more valid because it uses more mathematics. </span>
