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TiliK225 [7]
3 years ago
15

Which best describes why scientific models change over time?

Physics
1 answer:
irina1246 [14]3 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below are the choices and the answer is <span>B. 
</span>a.) Models can be changed by scientists who are more famous than previous scientists. 
<span>b.) As technology advances, new experiments often expose problems in accepted theories. </span>
<span>c.) Scientists tend to value new theories because they are more exciting. </span>
<span>d.) A newer theory is more valid because it uses more mathematics. </span>

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What is the acceleration of a 30.0-kg go kart if the thrust of its engine is 300.0 N?
VikaD [51]

Answer : a=10\ m/s^2

Explanation :

It is given that,

Mass of the engine, m = 30 kg

Thrust is equivalent to the force acting perpendicularly and it is F = 300 N

According to Newton's second law of motion :

F = m\times a

a is the acceleration of the engine.

a=\dfrac{F}{m}

a=\dfrac{300\ N}{30\ Kg}

a=10\ m/s^2

So, the acceleration of the engine is 10\ m/s^2.

Hence, this is the required solution.

5 0
3 years ago
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The mineral barite is
Damm [24]
A natural rock formation. Hope this helped.
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3 years ago
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Which type of element typically loses an electron to become an ion?
timofeeve [1]
Your answer should be metal
3 0
3 years ago
A filing cabinet weighing 556 N rests on the floor. The coefficient of static friction between it and the floor is 0.68, and the
zvonat [6]

Explanation:

"Static friction is a force that keeps an object at rest. It must be overcome to start moving the object."

(556 x 0.68) = static friction of 378.08N. before movement occurs.

The  forces (a) and (b) will not move it.  

Each will incur a frictional force preventing movement equal to itself, = 222N. and 334N. respectively.

Forces (c) and (d) will move it, and accelerate it.

Forces (c) and (d) will both encounter friction of (556 x 0.56) = 311.36N. when the cabinet is moving.

5 0
3 years ago
Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc
kumpel [21]

Answer:\frac{D_A}{v_B-v_A}

Explanation:

Given

car A had a head start of D_A

and it starts at x=0 and t=0

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where d_a is the distance travel by car A in time t

distance travel by car A is

d_a=v_A\times t

For car B with  speed v_B

d_B=D_A+d_a

v_B\times t=D_A+v_A\times t

t=\frac{D_A}{v_B-v_A}

7 0
3 years ago
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