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ozzi
3 years ago
11

Does anyone know how to solve for a proof like this??? PLEASE PLEASE HELP ME.

Mathematics
1 answer:
Sonbull [250]3 years ago
5 0

You are supposed to make a claim then prove it using evidence you are already given.

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Addition property of equality: if angle J equals 30 the angle j plus angle k equals?
gulaghasi [49]
The angle j plus angle k would equal
30j+k
5 0
3 years ago
Which is a better estimate for the weight of a double-decker bus
tia_tia [17]

Step-by-step explanation:

Coaches are typically sized to a height of 4.38 meters, whereas 'high-bridge' vehicles are usually around 20 centimeters higher. At an average height of 18.65 metres, integrated double-deckers are often permitted .

3 0
3 years ago
Please help, photo attached.
steposvetlana [31]

The zeroes of the polynomial functions are as follows:

  • For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
  • For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
  • For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

<h3>What are the zeroes of a polynomial?</h3>

The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.

The polynomials are given as follows:

f(x) = 2x(x - 3)(2 - x)

f(x) = 2(x - 3)²(x + 3)(x + 1)

f(x) = x³(x + 2)(x - 1)

For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2

For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1

For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1

In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.

Learn more about polynomials at: brainly.com/question/2833285

#SPJ1

5 0
2 years ago
What is the value of x in the eqation 5[x-6] = 2 [x+3]
topjm [15]

Answer:

x = 12

Step-by-step explanation:

5x - 30 = 2x + 6

3x = 36

x = 12

8 0
3 years ago
Read 2 more answers
Can someone help me answer this please
sveta [45]

( - 14) \div 7 = ( - 2)
3 0
4 years ago
Read 2 more answers
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