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Kipish [7]
3 years ago
10

if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds​

Physics
2 answers:
natta225 [31]3 years ago
5 0

Hope you could understand.

If you have any query, feel free to ask.

VLD [36.1K]3 years ago
4 0

Answer:

The ball took 0.4 seconds

Explanation:

» From the second newton's equation of motion.

{ \boxed{ \tt{s = ut +  \frac{1}{2} {gt}^{2}  }}}

  • s is displacement, s = 80cm, s = 0.8 meters
  • u is initial velocity, u = 0 [ from rest ]
  • g is 10 m/s²

{ \tt{0.8 = (0 \times t) + ( \frac{1}{2}  \times 10 \times  {t}^{2} )}} \\  \\ { \tt{0.8 = 5 {t}^{2} }} \\ { \tt{ {t}^{2} = 0.16 }} \\ { \tt{t =  \sqrt{0.16} }} \\  \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \:  \: }}}}

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