Question

if a ball is released from a height 80cm how long would it take the ball to reach the ground when g= 10m per seconds​

Answer 1

Hope you could understand.

If you have any query, feel free to ask.

Answer 2

Answer:

The ball took 0.4 seconds

Explanation:

» From the second newton's equation of motion.

${ \boxed{ \tt{s = ut + \frac{1}{2} {gt}^{2} }}}$

• s is displacement, s = 80cm, s = 0.8 meters
• u is initial velocity, u = 0 [ from rest ]
• g is 10 m/s²

${ \tt{0.8 = (0 \times t) + ( \frac{1}{2} \times 10 \times {t}^{2} )}} \\ \\ { \tt{0.8 = 5 {t}^{2} }} \\ { \tt{ {t}^{2} = 0.16 }} \\ { \tt{t = \sqrt{0.16} }} \\ \\ { \underline{ \underline{ \tt{ \: time = 0.4 \: seconds \: \: }}}}$