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KiRa [710]
3 years ago
9

Part V: If −1 is one of the roots of H(x) = x3 − 7x2 − x + 7, use synthetic division to find the resulting quadratic expression.

Hint: If −1 is a root, (x + 1) is the factor. (2 points)
Part VI: Factor the quadratic expression from Part V to find the final 2 factors and roots. (2 points)
Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
5 0
Solve for x over the real numbers:
x^3 - 7 x^2 - x + 7 = 0
The left hand side factors into a product with three terms:
(x - 7) (x - 1) (x + 1) = 0
Split into three equations:
x - 7 = 0 or x - 1 = 0 or x + 1 = 0
Add 7 to both sides:
x = 7 or x - 1 = 0 or x + 1 = 0
Add 1 to both sides:
x = 7 or x = 1 or x + 1 = 0
Subtract 1 from both sides:
Answer:  x = 7 or x = 1 or x = -1
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China's population is 1.446×10^9 . Marshall Islands's population is 6.025×10^4 . How many times larger is China's population tha
SVEN [57.7K]
(1.446×10^9) ÷ (<span>6.025×10^4)
= 0.24 x 10^5
= 2.4 x 10^4

answer

</span>2.4 x 10^4
3 0
4 years ago
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Which polynomials, given in square inches, could represent the area of a square with whole number side lengths if x is a whole n
Alex73 [517]

Answer:

~x2 − 4x + 4; ~x2 + 10x + 25

Step-by-step explanation:

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6 0
3 years ago
An adult blinks about 450 times in 30 minutes. A 12 year old blinks 150 times in 15 minutes. How many more times does an adult b
liq [111]
One way to figure this out is  to you can set up two equivalent fraction problems to figure out in both cases how many times the adult and twelve year old each blink in 60 minutes.

Adult blinks: \frac{450}{30}  =  \frac{?}{60}

Child blinks: \frac{150}{15}  =  \frac{?}{60}

In the "adult blinks" problem, you know that 30 is half of 60 - you can then multiply the numerator 450 x 2 to get 900 blinks per 60 min.

In the "child blinks" problem, 15 is one-quarter of 60, so you can multiply the numerator 150 x 4 to get 600 blinks per 60 min.

You can then just subtract the two new numerators, 900 - 600, to find that the adult blinks 300 more times than the 12-year-old in 60 minutes. 

5 0
3 years ago
Read 2 more answers
What’s the square route of 169
Mazyrski [523]

Answer:

± 13

Step-by-step explanation:

\sqrt{169} = ± 13, since

13 × 13 = 169 and - 13 × - 13 = 169

3 0
3 years ago
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Which choices are real numbers? Check all that apply. (-22)½ (-16)⅓ (-16)⅕ (-10)¼
8_murik_8 [283]

(-22)^{\frac{1}{2}} and (-10)^{\frac{1}{4}} are not real numbers

<h3><u>Solution:</u></h3>

A real number is any positive or negative number. This includes all integers and all rational and irrational numbers

They are called "Real Numbers" because they are not Imaginary Numbers.

When you take an even root of a negative number, there is no real answer. (2 is an even number)

In the real number set, you can't take an even-indexed root of a negative number.

Given options are:

\begin{array}{l}{\text { A) }(-22)^{\frac{1}{2}}} \\\\ {\text { B) }(-16)^{\frac{1}{3}}} \\\\ {\text { C) }(-16)^{\frac{1}{5}}} \\\\ {\text { D) }(-10)^{\frac{1}{4}}}\end{array}

Looking at the answer choices here, we can see that A and D use even roots, so they will give non-real answers.

Thus (-22)^{\frac{1}{2}} and (-10)^{\frac{1}{4}} are not real numbers

6 0
3 years ago
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