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vesna_86 [32]
2 years ago
5

The power ratings of several motors are listed in the table. A 2 column table with 3 rows. The first column is labeled motor wit

h entries, brand X, brand Y, brand Z. The second column is labeled Power in watts with entries 7460, 7650, 7580. An advertising agency writes marketing material for a new motor (Brand W) that has a power rating of 7,640 W. Which statement comparing the motors can they truthfully use? Brand W motor can finish any job faster than Brand Y motor can. There’s not a more powerful motor available. Brand W motor does more work each second than Brand X or Brand Z. Every second, Brand W motor does 7,640 N of your toughest work.
Physics
1 answer:
Lapatulllka [165]2 years ago
7 0

The statement  " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

Advertisement Rules:

  • An advertiser can not compare its products using the other companies name.
  • An advertiser can not make the false statement in its advertisement.

Here, the brand-W has the power rating of  7,640 W that is less than brand-Y. Advertiser cannot compare his brand using the name of Brand X, Y, or Z.

Therefore, the statement  " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

To know more about Advertisement Rules:

brainly.com/question/13679377

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a coil has n turns enclosing an area of a. in a physics laboratory experiment, the coil is rotated during the time interval δt f
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Here are the follow-up questions:

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3 years ago
Was the cannonball able to hit its target of 50 meters when the initial velocity was 20 m/s? Why?/Why Not?
frosja888 [35]

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

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Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

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