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vesna_86 [32]
2 years ago
5

The power ratings of several motors are listed in the table. A 2 column table with 3 rows. The first column is labeled motor wit

h entries, brand X, brand Y, brand Z. The second column is labeled Power in watts with entries 7460, 7650, 7580. An advertising agency writes marketing material for a new motor (Brand W) that has a power rating of 7,640 W. Which statement comparing the motors can they truthfully use? Brand W motor can finish any job faster than Brand Y motor can. There’s not a more powerful motor available. Brand W motor does more work each second than Brand X or Brand Z. Every second, Brand W motor does 7,640 N of your toughest work.
Physics
1 answer:
Lapatulllka [165]2 years ago
7 0

The statement  " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

Advertisement Rules:

  • An advertiser can not compare its products using the other companies name.
  • An advertiser can not make the false statement in its advertisement.

Here, the brand-W has the power rating of  7,640 W that is less than brand-Y. Advertiser cannot compare his brand using the name of Brand X, Y, or Z.

Therefore, the statement  " Brand-W motor does 7,640 N of your toughest work." can be truthfully use.

To know more about Advertisement Rules:

brainly.com/question/13679377

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During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t
tia_tia [17]

1.A) 4.9 m  

AL2006 Ace

The instant it was dropped, the ball had zero speed.


After falling for 1 second, its speed was 9.8 m/s straight down (gravity).


Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.


Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.


ANYTHING you drop does that, if air resistance doesn't hold it back.


Read more on Brainly.com - brainly.com/question/11776597#readmore

2 idk sorry

5 0
3 years ago
Read 2 more answers
Recall from Chapter 1 that a watt is a unit of en- ergy per unit time, and one watt (W) is equal to one joule per second ( J·s–1
harkovskaia [24]

Answer:

Explanation:

The energy of a photon is given by the equation E_p=h f, where h is the <em>Planck constant</em> and f the frequency of the photon. Thus, N photons of frequency f will give an energy of E_N=N h f.

We also know that frequency and wavelength are related by f=\frac{c}{\lambda}, so we have E_N=\frac{N h c}{\lambda}, where c is the <em>speed of light</em>.

We will want the number of photons, so we can write

N=\frac{\lambda E_N}{h c}

We need to know then how much energy do we have to calculate N. The equation of power is P=E/t, so for the power we have and considering 1 second we can calculate the total energy, and then only consider the 4% of it which will produce light, or better said, the N photons, which means it will be E_N.

Putting this paragraph in equations:

E_N=(\frac{4}{100})E=0.04Pt=(0.04)(100W)(1s)=4J.

And then we can substitute everything in our equation for number of photons, in S.I. and getting the values of constants from tables:

N=\frac{\lambda E_N}{h c}=\frac{(520 \times10^{-9}m) (4J)}{(6.626\times10^{-34}Js) (299792458m/s)}=1.047 \times10^{19}

3 0
3 years ago
by how many times occur in the force of attraction between two bodies change when the distance between then is reduced to one th
xenn [34]

Answer:

<em>The force is now 9 times the original force</em>

Explanation:

<u>Coulomb's Law </u>

The electrostatic force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

Coulomb's formula is:

\displaystyle F=k\frac{q_1q_2}{d^2}

Where:

k=9\cdot 10^9\ N.m^2/c^2

q1, q2 = the particles' charge

d= The distance between the particles

Suppose the distance is reduced to d'=d/3, the new force F' is:

\displaystyle F'=k\frac{q_1q_2}{\left(\frac{d}{3}\right)^2}

\displaystyle F'=k\frac{q_1q_2}{\frac{d^2}{9}}

\displaystyle F'=9k\frac{q_1q_2}{d^2}

\displaystyle F'=9F

The force is now 9 times the original force

8 0
3 years ago
The venn diagram shown below compares the nuclear reactions in the sun and nuclear power plants.
BARSIC [14]

Answer:

Formation of new elements

Explanation:

3 0
3 years ago
Suzette had prepared the graph below to add to her lab
Charra [1.4K]

Answer:

A title

Explanation:

Because this is middle school.

4 0
3 years ago
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