The angular frequency of this motion is 5.46 rad/s.
The oscillation of spring is an example of Simple Harmonic Motion(SHM).
The general equation of an SHM is given by the formula.
X = Acos(wt)
Here A is the amplitude
ω is the angular frequency
T is the time
Comparing the above equation with the given condition,
X = 17.4 cm cos(5.46t)
A = 17.4 cm
ω = 5.46 rad/s
T = 1 s
Hence, the angular frequency of this motion is 5.46 rad/s.
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The answer of this question is (c) is always more
Answer: Mathematical Model
Explanation:
Took the test
D)
Explanation:
Coz the position changes with time but the position change is not constant throughout time So, D) does not have constant velocity
Answer:
B) Its velocity is perpendicular to the acceleration.
Explanation:
For general projectile motion, the horizontal acceleration is 0 and the vertical acceleration is -g. This is true for all points on the trajectory.
At the highest point, the vertical velocity is 0. So you have only a horizontal velocity as well as a vertical acceleration. So the two are perpendicular.
