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4 years ago

Which is a common cause of incomplete combustion

2 answers:

5 0

During complete combustion carbon and hydrogen combine with oxygen (O2) to produce carbon dioxide (CO2) and water (HO2) during that time it is not completely oxidized producing soot or carbon monoxide

valentina_108 [34]4 years ago

4 0

Answer: incomplete supply of oxygen

Explanation:

Combustion is a chemical reaction in which a fuel is reacted with excess supply of oxygen to result into complete oxidation of fuel to give carbon dioxide and water.

Example of complete combustion :

$C+O_2 \rightarrow CO_2$

Incomplete combustion happens when the supply of oxygen is limited and thus fuel can not be completely oxidized , thus forming carbon monoxide.

Example of incomplete combustion :

$C+\frac{1}{2}O_2\rightarrow CO$

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What is the force weight of a jaguar who jumps 3 meters to a tree branch with 2670 J of work?

fgiga [73]

Answer:

$we \: know \: energy \: = \: force \: \times distance \\ e = f \times d \\ so \: f \: = \frac{e}{d} \\ so \: th \: force \: here \: = (\frac{2670}{3}) newton \\ = 890newton$

Hope it helps

7 0

3 years ago

I have a 3 cc piece of aluminum with a density of steel with a mass of 24.0 g. I cut it into 2 equal pieces. How has the density

tresset_1 [31]

Answer:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

Explanation:

3 0

3 years ago

A 2.81 μF capacitor is charged to 1220 V and a 6.61 μF capacitor is charged to 560 V. These capacitors are then disconnected fro

fenix001 [56]

Answer:

756.88 Volts will be the potential difference across each capacitor.

Explanation:

$Q=C\times V$

Q = Charge on capacitor

C = Capacitance

V = Voltage across capacitor

Capacitance of first capacitor = $C_1=2.81 \mu F=2.81\times 10^{-6} F$

Charge of first capacitor = $Q_1$

Voltage across first capacitor = $V_1=1220 V$

$Q_1=C_1V_1$

$Q_1=2.81\times 10^{-6} F\times 1220 V=0.0034282 C$

Capacitance of first capacitor = $C_2=6.61\mu F=6.61\times 10^{-6} F$

Charge of second capacitor = $Q_2$

Voltage across first capacitor = $V_2=560 V$

$Q_2=C_2V_2$

$Q_1=6.61\times 10^{-6} F\times 560 V=0.0037016 C$

Both the capacitors are disconnected and positive plates are now connected to each other and the negative plates are connected to each other. These capacitors are connected in parallel combination.

Total charge = Q

$Q =Q_1+Q_2=0.0034282 C+ 0.0037016 C=0.0071298 C$

Total capacitance in parallel combination:

$C_p=C_1+C_2=2.81\times 10^{-6} F+6.61\times 10^{-6} F=9.42\times 10^{-6} F$

Potential across both capacitors = V

$V=\frac{Q}{C}=\frac{0.0071298 C}{9.42\times 10^{-6} F}=756.88 V$

756.88 Volts will be the potential difference across each capacitor.

8 0

3 years ago

I NEED THIS A SOON AS POSSIBLE

vivado [14]

Work is done when spring is extended or compressed. Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.

6 0

3 years ago

Read 2 more answers

A white light shines through a diffraction grating that is ruled at 900 lines/cm. A detector is 1.2 cm long and is to be used to

katrin [286]

Answer:

Explanation:

Given that,

Diffraction grating is ruled by 900 lines/cm

The detector length is

h= 1.2cm =1.2/100= 0.012m

Short wavelength is λs= 564.6nm

Long wavelength is λl = 571.2nm

Question: how far from the grating should the screen with the detector on it be placed. x=?

Since there are 900 lines per centimeter, each line is separated by 1/900 of a centimeter.

The distance between slits is d is given as

d = 1/900 cm

d = 0.00111cm

d = 0.0000111m = 1.11×10^-5 m

Let us call the two angles θs for short-wavelength (564.6nm) and θl for long-wavelength (571.2nm). Diffraction grating is given as

d sin(θs)= mλl

sin(θs)= mλl / d

Since we are given 7th order, then m=7

sin(θs)= 7×564.6×10^-9 / 1.11×10^-5

sin(θs)= 0.3557

θs = arcsin(0.3557)

θs = 20.84°

Applying the same principle for long wavelength

d sin(θl)= mλl

sin(θl)= mλl / d

Since we are given 7th order, then m=7

sin(θl)= 7×571.2×10^-9 / 1.11×10^-5

sin(θl)= 0.3599

θl = arcsin(0.3599)

θl = 21.1°

Using trigonometry,

Then, tanθ = opposite/adjacent

Adjacent is the distance between the screen and the detector

Opposite Is the length of detector, which serves like a height

Tanθl = h/x

x= h / Tan(θl)

x = 0.012 / Tan(21.1)

x = 0.0311m

x =3.11cm

Check attachment for better understanding the how I used the trigonometric function and the triangle I used.

5 0

3 years ago