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3 years ago

Which is a common cause of incomplete combustion

2 answers:

5 0

During complete combustion carbon and hydrogen combine with oxygen (O2) to produce carbon dioxide (CO2) and water (HO2) during that time it is not completely oxidized producing soot or carbon monoxide

valentina_108 [34]3 years ago

4 0

Answer: incomplete supply of oxygen

Explanation:

Combustion is a chemical reaction in which a fuel is reacted with excess supply of oxygen to result into complete oxidation of fuel to give carbon dioxide and water.

Example of complete combustion :

$C+O_2 \rightarrow CO_2$

Incomplete combustion happens when the supply of oxygen is limited and thus fuel can not be completely oxidized , thus forming carbon monoxide.

Example of incomplete combustion :

$C+\frac{1}{2}O_2\rightarrow CO$

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How does wood and plastic relate to forces

WARRIOR [948]

Answer:

There are six kinds of forces that act on objects when they come into contact with one another: Normal force, applied force, frictional force, tension force, spring force and resisting force. These forces make objects change their motion or movement , the act of going from one place to another.

6 0

3 years ago

one of the four wave interactions is very important to how plants use light to grow. guess which interaction this is

KiRa [710]

The photosynthetic wave interaction between visible light and a photosensitive part of a plant is very important t how plants use light to grow.
The frequency range and intensity levels of this light, I don't know.

Maybe the above ???

6 0

3 years ago

A 5.00 gram bullet moving at 600 m/s penetrates a tree trunk to a depth of 4.00 cm.

Crazy boy [7]

A) Work energy relation;
Work =ΔKE ; work done = Force × distance, while, Kinetic energy = 1/2 MV²
F.s = 1/2mv²
F× 4×10^-2 = 1/2 × 5 ×10^-3 × (600)²
F = 900/0.04
= 22500 N
Therefore, force is 22500 N

b) From newton's second law of motion;
F = Ma
Thus; a = F/m
= 22500/(5×10^-3)
= 4,500,000 m/s²
But v = u-at
0 = 600- 4500,000 t
t = 1.33 × 10^-4 seconds

6 0

3 years ago

Explain the characteristics of the Gypsum Hills regionIf we have a sample of silicon (Si) atoms that has 14 protons, 14 electron

amid [387]

Answer:

second one

Explanation:

8 0

3 years ago

Compute the expected shell-model quadrupole moment of 209Bi () and compare with the experimental value, - 0.37 b

Over [174]

Answer:

0.22 b

Explanation:

Quadrupole moment of the nucleon is,

$Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2}$

And also,

$R^{2}=R^{2} _{0}A^{\frac{2}{3} }$

And, $R _{0}=1.2\times 10^{-15}m$

Now,

$Q=-\frac{2j-1}{2(j+1)}\frac{3}{5}R^{2} _{0}A^{\frac{2}{3} }$

For Bismuth $j=\frac{9}{2}$ and A is 209.

$Q=-\frac{2\frac{9}{2} -1}{2(\frac{9}{2} +1)}\frac{3}{5}(1.2\times 10^{-15}) ^{2}(209)^{\frac{2}{3} }\\Q=0.628\times 35.28\times 10^{-30} \\Q=22.15\times 10^{-30} m^{2} \\Q=0.2215\times 10^{-28} m^{2} \\Q=0.22 barn$

Therefore, the expected value of quadrupole is 0.22 b which is quite related with experimental value which is 0.37 b

3 0

3 years ago