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KonstantinChe [14]
3 years ago
13

A ballistics test involves firing a 10.0g bullet horizontally into a 1.50kg wood block that is initially at rest. The bullet bec

omes lodged in the block, and you determine that they move together at a speed of 5.00m/s. With this information, determine the velocity of the bullet before it entered the block.
Physics
1 answer:
wariber [46]3 years ago
4 0

Answer:

u= 755 m/s

Explanation:

Lets take

Velocity of bullet = u m/s

The velocity of system after collision ,v= 5 m/s

m= 10 g = 0.01 kg

M= 1.5 kg

From linear momentum conservation( because there is no any external force on the system)

Pi= Pf

m u  = ( m +m) v

0.01 x u= (1.5 + 0.01) x 5

u= 755 m/s

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Answer:

They have no freedom to move

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Particles can be solids, liquids and gases.

Solids are the substances in which the atoms are very close to each other. It is very difficult to separate the molecules. The atoms cannot move from one place to another.  The inter molecular forces between them is very strong.

Hence, the correct option that describes the movement of atoms in a solid is (c) "They have no freedom to move".

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Which term defines the energy of motion?
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In serving, a tennis player accelerates a 59 g tennis ball horizontally from rest to a speed of 34 m/s Assuming that the acceler
Akimi4 [234]

Answer:

The magnitude of the force exerted on the ball by the racquet is 94.73 N.

Explanation:

The force exerted on the ball is the following:

F = ma

Where:

m: is the mass of the ball = 59 g

a: is the acceleration

The acceleration of the ball can be found with the following kinematic equation:

v_{f}^{2} = v_{0}^{2} + 2ad

Where:

d: is the distance = 0.36 m

v_{f}: is the final speed = 34 m/s

v_{0}: is the initial speed = 0 (it start from rest)

Hence, the acceleration is:

a = \frac{v_{f}^{2}}{2d} = \frac{(34 m/s)^{2}}{2*0.36 m} = 1605.6 m/s^{2

Finally, the force is:

F = ma = 59 \cdot 10^{-3} kg*1605.6 m/s^{2} = 94.73 N    

Therefore, the magnitude of the force exerted on the ball by the racquet is 94.73 N.                                

                                                                 

I hope it helps you!                                                              

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3 years ago
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