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KonstantinChe [14]
3 years ago
13

A ballistics test involves firing a 10.0g bullet horizontally into a 1.50kg wood block that is initially at rest. The bullet bec

omes lodged in the block, and you determine that they move together at a speed of 5.00m/s. With this information, determine the velocity of the bullet before it entered the block.
Physics
1 answer:
wariber [46]3 years ago
4 0

Answer:

u= 755 m/s

Explanation:

Lets take

Velocity of bullet = u m/s

The velocity of system after collision ,v= 5 m/s

m= 10 g = 0.01 kg

M= 1.5 kg

From linear momentum conservation( because there is no any external force on the system)

Pi= Pf

m u  = ( m +m) v

0.01 x u= (1.5 + 0.01) x 5

u= 755 m/s

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Answer:

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Explanation:

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The volume of air contained in the bicycle pump, V₁ = 20 cm³

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The volume (available) of the tyre, where the air is pumped, V₂ = 100 cm³

Let P₂ represent the pressure in the tyre after the air is pumped

By Boyle's law, we have that at constant temperature, the volume of a given mass of gas is inversely proportional to its pressure;

Mathematically, Boyle's law gives the following equation;

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∴ P₂ = (P₁ × V₁)/V₂

Substituting the known values gives;

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P₂ = 20 kPa

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