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Fynjy0 [20]
2 years ago
14

What is 3 3/5 + 5 4/6?

Mathematics
1 answer:
irga5000 [103]2 years ago
5 0

Answer:

9 4/15

Step-by-step explanation:

3 3/5 + 5 4/6

First 3+5=8

Then find a common denominator

So 3/5*6/6=

3*6=18  5*6=30

18/30

4/6*5/5=

4*5=20  6*5=30

20/30

18/30+20/30=1 8/30

8+1 8/30=9 8/30

Which simplifies to 9 4/15

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Which of the following problems represents the following:
madam [21]

Answer:

D

Step-by-step explanation:

"Turn around phrase" just means that you are subtracting the last number minus the first number. Subtracting the negative number is written as -(-34.7)

5 0
3 years ago
11x - 8y = -4<br> -4x + 3y = 2
Leto [7]

Answer:

x=4, y=6. (4, 6).

Step-by-step explanation:

11x-8y=-4

-4x+3y=2

----------------

4(11x-8y)=4(-4)

11(-4x+3y)=11(2)

-------------------------

44x-32y=-16

-44x+33y=22

-------------------

y=6

11x-8(6)=-4

11x-48=-4

11x=-4+48

11x=44

x=44/11

x=4

6 0
3 years ago
H
erastovalidia [21]
It would be C. It’s the most valuable answer to the equation. I did my caclucations
3 0
3 years ago
A rectangle has the length of 22 inches less than 7 times the width. If the area of the rectangle is 3197 square inches, find th
Nikolay [14]

The length of rectangle is 139 inches

Solution:

Given that, area of the rectangle is 3197 square inches

Let "L" be the length of rectangle and "W" be the width of rectangle

Also given that rectangle has the length of 22 inches less than 7 times the width

Length = 7 times width - 22

L = 7W - 22

<em><u>The area of rectangle is given as:</u></em>

\text {Area of rectangle }=\text { length } \times \text { width }

Substituting the values we get,

\begin{array}{l}{3197=(7 W-22)(W)} \\\\ {3197=7 W^{2}-22 W} \\\\ {7 W^{2}-22 W-3197=0}\end{array}

On solving the above quadratic equation using quadratic formula,

\text {For the quadratic equation } a x^{2}+b x+c=0 \text { where } a \neq 0

x=\frac{-b \pm \sqrt{\left(b^{2}-4 a c\right)}}{2 a}

\begin{array}{l}{\text {Here in } 7 \mathrm{W}^{2}-22 \mathrm{W}-3197=0} \\\\ {a=7 ; b=-22 ; c=-3197}\end{array}

Substituting in above quadratic formula,

\begin{array}{l}{W=\frac{-(-22) \pm \sqrt{\left((-22)^{2}-4(7)(-3197)\right)}}{2 \times 7}} \\\\ {W=\frac{22 \pm \sqrt{90000}}{14}=\frac{22 \pm 300}{14}} \\\\ {W=\frac{22+300}{14} \text { or } W=\frac{22-300}{14}} \\\\ {W=23 \text { or } W=-19.85}\end{array}

Since width of rectangle cannot be negative, ignore negative value of "W"

So width W = 23 inches

Length L = 7W - 22 = 7(23) - 22 = 139 inches

Thus length of rectangle is 139 inches

8 0
4 years ago
What emits light?<br>*ATP, luciferin,luciferase,or exygen
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The answer would be ATP because oxygen supplies the energy and the others regulate and control it.
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