Question

Help ASAP" id="TexFormula1" title=" \frac{x - 3}{5} = \frac{x + 5}{3} " alt=" \frac{x - 3}{5} = \frac{x + 5}{3} " align="absmiddle" class="latex-formula">
Find the value of x​

Answer 1

$\dfrac{x-3}5 = \dfrac{x+5}3 \\\\\implies 3(x-3) = 5(x+5)\\\\\implies 3x - 9 = 5x +25\\\\\implies 5x -3x +25 +9 =0\\\\\implies 2x +34 =0\\\\\implies 2x = -34 \\\\\implies x = -\dfrac{34}2 =-17$

Answer 2

$\sf \longmapsto \: \dfrac{x - 3}{5} = \dfrac{ x + 5}{3}$

$\sf \longmapsto \: 3(x - 3) = 5(x + 5)$

$\sf \longmapsto \: 3x - 9 = 5x + 25$

$\sf \longmapsto3x - 5x = 25 + 9$

$\sf \longmapsto - 2x = 34$

$\sf \longmapsto \: x = \dfrac{34}{ - 2}$

$\sf \longmapsto \: x =- \cancel \dfrac{34}{ 2}$

$\sf \longmapsto \: x = - 17$

$\boxed{\Rightarrow\: x = - 17}$