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1 year ago

What is the exact circumference of the circle? A. 10 FT B. 20 FT C. 40 FT D. 60 FT

Mathematics

1 answer:

valentina_108 [34]1 year ago

8 0

Answer:

D. 60 Ft

Step-by-step explanation:

circumference = πd

π 20

60ft

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Mhanifa please help with this

Fed [463]

Answer:

<u>Use cross-multiplication to solve these</u>

1) 6/2 = 4/p ⇒ 6p = 4*2 ⇒ p = 8/6 ⇒ p = 4/3
2) 4/k = 8/2 ⇒ 8k = 2*4 ⇒ k = 8/8 ⇒ k = 1
3) n/4 = 8/7 ⇒ n = 4*8/7 ⇒ n = 32/7
4) 5/3 = x/4 ⇒ x = 4*5/3 ⇒ x = 20/3

8 0

2 years ago

What is the perimeter of the square 3 by 3

Tema [17]

Answer:12cm

Step-by-step explanation:3+3+3+3 because its 3x3 so their is 3cm on each side

5 0

2 years ago

Bo and Erica are yoga instructors. Between the two of them, they teach 45 yoga classes each week. If Erica teaches 15 fewer than

Solnce55 [7]

Answer:

20 and 25.

Step-by-step explanation:

Given:

They both teach total 45 yoga classes each week.

Erica teaches 15 fewer than twice as many as Bo.

To find:

How many classes does each instructor teach per week = ?

Solution:

Let number of classes are taken by Bo = $x$

Then number of classes are taken by Erica = $2x - 15$ (given)

Total number of classes are taken by both = 45 (given)

According to the question.

$x$ + $2x - 15$ = 45

$3x - 15 = 45$

By adding both side by 15

$3x = 60\\$

By dividing both side by 3

$x = 20$

number of classes are taken by Bo = $x$ = 20

number of classes are taken by Erica = $2x - 15$

= $2\times20 - 15 = 40- 15 = 25\\$

Therefore, number of classes are taken by Bo and Erica is 20 and 25.

6 0

3 years ago

Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

<u>I will try to give as many details as possible. </u>

First of all, I just would like to say:

$\text{Use } \LaTeX !$

Texting in Latex is much more clear and depending on the question, just writing down without it may be confusing or ambiguous. Be together with Latex! （＊＾Ｕ＾）人（≧Ｖ≦＊）/

$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

4 0

2 years ago

Which mixed number is equivalent to this decimal?

kogti [31]

D is correct because it is a tenth and it becomes a hundredth

4 0

2 years ago

Read 2 more answers