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Tamiku [17]
2 years ago
13

Use suitable identity and find the product of: (2a-7)(2a-7)

Mathematics
2 answers:
NeTakaya2 years ago
5 0

\\ \sf\longmapsto (2a-7)(2a-7)

\\ \sf\longmapsto (2a-7)^2

  • (a-b)^2=a^2+b^2-2ab

\\ \sf\longmapsto 2a^2-2(2a)(7)+49

\\ \sf\longmapsto 4a^2-28a+29

Georgia [21]2 years ago
3 0

Answer:

=4a2−28a+49

Step-by-step explanation:

(2a−7)(2a−7)

=(2a+−7)(2a+−7)

=(2a)(2a)+(2a)(−7)+(−7)(2a)+(−7)(−7)

=4a2−14a−14a+49

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f(0) = 2(3)(0) = 0  ⇒  (0, 0)

f(1) = 2(3)(1) = 6  ⇒  (1, 6)

<u>rate of change from x = 0 to x = 1</u>

\frac{y2 - y1}{x2 - x1} = \frac{6 - 0}{1 - 0} = \frac{6}{1} = 6

******************************************

f(2) = 2(3)(2) = 12  ⇒  (2, 12)

f(3) = 2(3)(3) = 18  ⇒  (3, 18)

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Since it is the same line, they will have the same slope (aka rate of change).

5 0
3 years ago
???? please help lol
kow [346]

Answer:

  1. 150π ft²
  2. 10π ft.

Step-by-step explanation:

Area of the sector :

Area (sector) = \pi r^{2} \times \frac{\theta}{360^{o}}

Finding the area given r = 30 ft. and θ = 60° :

⇒ Area = π × (30)² × 60/360

⇒ Area = π × 900/6

⇒ Area = 150π ft²

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Length of the arc :

Length (arc) =2 \pi r} \times \frac{\theta}{360^{o}}

Finding the arc length given r = 30 ft. and θ = 60° :

⇒ Arc Length = 2 × π × 30 × 60/360

⇒ Arc Length = 60/6 × π

⇒ Arc Length = 10π ft.

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