Answer:
x = ±3 sqrt(2)
Step-by-step explanation:
x^2 + x^2=6^2
Combine like terms
2x^2 = 6^2
Divide each side by 2
x^2 = * 6^2/2
Take the square root of each side
sqrt(x^2) =± sqrt( 6^2/2)
Remember that sqrt(a/b) = ±sqrt(a ) /sqrt(b)
x = ±sqrt(6^2)/sqrt(2)
x = ±6 /sqrt(2)
We do not leave square roots in the denominator, so we multiply the top and bottom by sqrt(2)
x = ±6 /sqrt(2) * sqrt(2)/ sqrt(2)
x = ±6 *sqrt(2) /( sqrt(2)*sqrt(2))
x = ±6 sqrt(2) /(2)
x = ±3 sqrt(2)
To find the gradient of a line we first hv to find the formula
so Gradient=√X1-x2and √y1-y2
((-2,1) and (0,-5)) line 1
line 2(0,-1) and (1,0)
first we will work for line 1
X1 is -2
X2 is -0
Y1 is 1
Y2 is -1
so y=x-1
so we substitute the values
1--1=-2--0
so,
1+1=-2+0
2=-2
-0
So the equation 1 line 1 is not true
we will now go to equation 2 line 2
the equation is 3x+y=-5
we substitute the values
3(-2--0)+1--1=-5
3(-2)+-2=-5
-6+-2=-5
-8= -5
group like terms
Ur answer should look like this -3
So the answer is 3x+y=-5
5.3 minutes.
First, let's calculate the volume of the tank. That will be the area of the base multiplied by it's length. And since it's base is a circle, the area is pi*r^2. So:
V = l*pi*r^2
V = 3.5 * pi * (2.2/2)^2
V = 3.5 * pi * (1.1)^2
V = 3.5 * pi * 1.21
V = 4.235 * pi
V = 13.30464489
So the tank has a volume of about 13.3 ft^3. Now simply divide that volume
by the rate of incoming fluid. So
13.3 / 2.5 = 5.32
Rounding to 2 significant figures gives a time of 5.3 minutes.
Answer:
Adam's way is correct
Step-by-step explanation:
11.3524 can easily be rounded to the nearest tenth because the number 4 cannot be rounded up. Any number below 4 cannot be rounded up and anything above five can be rounded up and that us why 5 rounded up transforms the 3 to a 4.
Hope this helped.
Answer: equally likely
Step-by-step explanation: I have a coin. My coin has 2 sides. I have a 50 percent chance of landing on ether side so equally likely.
