Use compound interest formula F=P(1+i)^n twice, one for each deposit and sum the two results.
For the P=$40,000 deposit,
i=10%/2=5% (semi-annual)
number of periods (6 months), n = 6*2 = 12
Future value (at end of year 6),
F = P(1+i)^n = 40,000(1+0.05)^12 = $71834.253
For the P=20000, deposited at the START of the fourth year, which is the same as the end of the third year.
i=5% (semi-annual
n=2*(6-3), n = 6
Future value (at end of year 6)
F=P(1+i)^n = 20000(1+0.05)^6 = 26801.913
Total amount after 6 years
= 71834.253 + 26801.913
=98636.17 (to the nearest cent.)
Hello,
f'(x) = sin(x) - 65 → f(x) = -cos(x) - 65x
Answer:
1536 cm^2 be the correct answ
12598 rounded to the nearest thousands is 1260
Let's simplify step-by-step.
<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b2
</span></span></span>There are no like terms.
Answer:
<span>=<span><span><span>a2</span>−<span><span>10a</span>b</span></span>+<span>3<span>b<span>2</span></span></span></span></span>
