Question

Math 13

Answer 1

Answer:

The area of polygon MNOPQR = Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units.

In the given polygon MNOPQR, side MN is parallel to side RQ and the side MR is parallel to side PQ

We will draw a perpendicular line from point O on the side RQ, which will intersect RQ at point S. So, we can now divide the whole polygon into two different rectangles MNSR and OPQS with the areas as A₁ and A₂ respectively.

In rectangle MNSR, length(MN) = 5 units and width (MR) = 3 units

According to the formula for Area of rectangle,

A₁ = (length)×(width)

A₁ = (5 units)×(3 units)

A₁ = 15 square units

Now in rectangle MNSR, side MN= side RS and side MR = side NS,

so RS= 5 units and NS= 3 units

That means, SQ= RQ- RS = 7-5 = 2 units

and OS= NS - NO = 3- 2 = 1 unit

In rectangle OPQS, we have length(SQ) = 2 units and width(OS) = 1 unit

So, A₂ = (length)×(width)

A₂ = (2 units)×(1 unit)

A₂ = 2 square units

So, the area of polygon MNOPQR = (Area of a rectangle that is 15 square units + Area of a rectangle that is 2 square units)

Step-by-step explanation:

Answer 2

Man said to much but right answer