Question

Write an equation that passes through (-2, - 11) and is perpendicular to x + 4y=8​

Answer 1

Answer:

y = 4x - 3

Step-by-step explanation:

Firstly rearrange into the form y = mx + c;

⇒ $y = -\frac{1}{4}x + 2$

Secondly, find the gradient of the line using the formula for perpendicular lines;

⇒ $m_{1}m_{2} = -1$

⇒ $-\frac{1}{4}m_{2} = -1$

⇒ $m_{2} = 4$

Now substitute into the formula for a straight line;

⇒ $y - y_{1} = m(x - x_{1})$

⇒ $y + 11 = 4(x + 2)$

⇒ $y = 4x - 3$